Answer with explanation:
The given differential equation is
y" -y'+y=2 sin 3x------(1)
Let, y'=z
y"=z'

Substituting the value of , y, y' and y" in equation (1)
z'-z+zx=2 sin 3 x
z'+z(x-1)=2 sin 3 x-----------(1)
This is a type of linear differential equation.
Integrating factor

Multiplying both sides of equation (1) by integrating factor and integrating we get


Answer:
$9257.5
Step-by-step explanation:
plug into the equation known variables
Answer:
-5 sorry if it's wrong. I tried.
Answer:
J Compound interest; $298.65
Step-by-step explanation:
Interest compounding pays interest on the interest. For the same annual rate, any amount of compounding will earn more interest.
For short time periods, the effect of compounding is not great. In general, it will be a fraction of the equivalent simple interest rate. Here, the effective multiplier for annual compounding is ...
1.051^4 = 1.22024337
and the effective multiplier for simple interest is ...
1 +0.051·4 = 1.204
Then the difference in interest rate multiplier for the 4-year period is ...
1.22024337 -1.204 = 0.01614337
That fraction of the $18500 principal is $298.65.
Compound interest earns $298.65 more than simple interest in this scenario.
Hope this helps, have an amazing day!
Answer:
Step-by-step explanation:
T(1)=1=0*x^3 0*x^2 0*x 1*1 T(x)=x-1=0*x^3 0*x^2 1*x (-1)*1 T(x^2)=2x^2-6x 6=0*x^3 2*x^2 (-6)*x 6 T(x^3)=6x^3-48*x^2 141*x-141 T(x^4)=24*x^3-204*x^2 628*x-604*1 collect the coefficient matrix and take its transpose
0 0 0 6 24
0 0 2 -48 -204
0 1 -6 141 628
1 -1 6 -141 -604