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3 years ago

12

Please help me!i have problems with this question

1 answer:

Leno4ka [110]3 years ago

4 0

Answer:

the mass of the empty box is 4/3 kg.

Step-by-step explanation:

The total mass (box plus 4 books and 2 files) is 2 kg

When half of the load is removed (2 books and 2 files) the mass is 1 3/20.

We have the following equation:

2 kg - (x/2)= 1 3/20 kg

Where x is the total mass of the load (4 books and 2 files)

This steps where followed to solve the equation:

2 -x/2 = (20-3)/20

40-10x=17

23=10x

x=2/3 kg

That is the total mass of the load

Hence

2kg -2/3 kg= 4/3 kg, the mass of the box

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Ik this is really easy but I'm so tired rn xD Please helppp

crimeas [40]

Answer:

(20 - 13.75) / 5 = ?

$1.25 per bag of chips

Step-by-step explanation:

$20.00 - $13.75 = 6.25 was spent on chips total

$6.25 / 5 people = $1.25 per person (or per bag of chips)

(20 - 13.75) / 5 = ?

7 0

2 years ago

If the exchange rate between the American dollar and the Japanese yen is such that $4.00= 442 yen, how many yen could be exchang

Anna [14]

$6(442Y/$4)=663Y

So $4 is equivalent to 663 Yen

5 0

3 years ago

Read 2 more answers

Nathan earns $78.75 for working 5 hours. Calculate the unit rate. How much money does he earn in 1 hour?

Sladkaya [172]

Answer: $15.75

Step-by-step explanation:

$78.75/5 hr=$15.75/hr

3 0

1 year ago

Read 2 more answers

Intersection point of Y=logx and y=1/2log(x+1)

GalinKa [24]

Answer:

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

The Problem:

What is the intersection point of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ ?

Step-by-step explanation:

To find the intersection of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ , we will need to find when they have a common point; when their $x$ and $y$ are the same.

Let's start with setting the $y$ 's equal to find those $x$ 's for which the $y$ 's are the same.

$\log(x)=\frac{1}{2}\log(x+1)$

By power rule:

$\log(x)=\log((x+1)^\frac{1}{2})$

Since $\log(u)=\log(v)$ implies $u=v$ :

$x=(x+1)^\frac{1}{2}$

Squaring both sides to get rid of the fraction exponent:

$x^2=x+1$

This is a quadratic equation.

Subtract $(x+1)$ on both sides:

$x^2-(x+1)=0$

$x^2-x-1=0$

Comparing this to $ax^2+bx+c=0$ we see the following:

$a=1$

$b=-1$

$c=-1$

Let's plug them into the quadratic formula:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{1 \pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}$

$x=\frac{1 \pm \sqrt{1+4}}{2}$

$x=\frac{1 \pm \sqrt{5}}{2}$

So we have the solutions to the quadratic equation are:

$x=\frac{1+\sqrt{5}}{2}$ or $x=\frac{1-\sqrt{5}}{2}$ .

The second solution definitely gives at least one of the logarithm equation problems.

Example: $\log(x)$ has problems when $x \le 0$ and so the second solution is a problem.

So the $x$ where the equations intersect is at $x=\frac{1+\sqrt{5}}{2}$ .

Let's find the $y$ -coordinate.

You may use either equation.

I choose $y=\log(x)$ .

$y=\log(\frac{1+\sqrt{5}}{2})$

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

6 0

2 years ago

ariel is saving money for a new computer that costs $650. she has $150, which she puts into an account. then she adds $25 each w

Oksanka [162]

20 weeks

The initial equation is 25x+150=650. Since she already has 150, we can subtract that from the total to get 500. We now have that 25x=500. Divide by 25 on both sides to get 20 weeks

:)

5 0

3 years ago