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3 years ago

I need help with this

Mathematics

2 answers:

german3 years ago

5 0

What you need to do is look at the number in each of the places listed and if the number to the right of it is above five make it go up one if it is below make it go down one

Olegator [25]3 years ago

3 0

On the row of 0.9608 the answers are:
1, 0.96, 0.960
The row of 0.0274:
0, 0.02, 0.03
On the row of 6.0085:
6, 6.00, 6.01

You might be interested in

Solve for x, rounding to the nearest hundredth. 10^3x = 98

Anna71 [15]

Answer:

see explanation

Step-by-step explanation:

10^3x=98

1000x=98

x=98/1000

x=49/500

x=0.98

if it is rounded to the nearest hundredth then x=0

8 0

3 years ago

(43 points) In the US, 85% of the population has Rh positive blood. Suppose we take a random sample of 6 persons and let Y denot

VladimirAG [237]

Answer:

a) Binomial distribution with parameters p=0.85 q=0.15 n=6

b) 62.29%

c) 2.38%

d) See explanation below

Step-by-step explanation:

We could model this situation with a binomial distribution

$P(6;k)=\binom{6}{k}p^kq^{6-k}$

where P(6;k) is the probability of finding exactly k people out of 6 with Rh positive, p is the probability of finding one person with Rh positive and q=(1-p) the probability of finding a person with no Rh.

$\bf P(Y=k)=\binom{6}{k}(0.85)^k(0.15)^{6-k}$

The probability that Y is less than 6 is

P(Y=0)+P(Y=1)+...+P(Y=5)

Let's compute each of these terms

$P(Y=0)=P(6;0)=\binom{6}{0}(0.85)^0(0.15)^{6}=1.139*10^{-5}$

$P(Y=1)=P(6;1)=\binom{6}{1}(0.85)^1(0.15)^{5}=0.0000387281$

$P(Y=2)=P(6;2)=\binom{6}{2}(0.85)^2(0.15)^{4}=0.005486484$

$P(Y=3)=P(6;3)=\binom{6}{3}(0.85)^3(0.15)^{3}=0.041453438$

$P(Y=4)=P(6;4)=\binom{6}{4}(0.85)^4(0.15)^{2}=0.176177109$

$P(Y=5)=P(6;5)=\binom{6}{5}(0.85)^5(0.15)^{1}=0.399334781$

and adding up these values we have that the probability that Y is less than 6 is

$\sum_{i=1}^{5}P(Y=i)=0.622850484\approx 0.6229=62.29\%$

In this case is a binomial distribution with n=200 instead of 6.

p and q remain the same.

The mean of this sample would be 85% of 200 = 170.

In a binomial distribution, the standard deviation is

$s = \sqrt{npq}$

In this case

$\sqrt{200(0.85)(0.15)}=5.05$

Let's approximate the distribution with a normal distribution with mean 170 and standard deviation 5.05

So, the approximate probability that there are fewer than 160 persons with Rh positive blood in a sample of 200 would be the area under the normal curve to the left of 160

(see picture attached)

We can compute that area with a computer and find it is

0.0238 or 2.38%

d) In order to approximate a binomial distribution with a normal distribution we need a large sample like the one taken in c).

In general, we can do this if the sample of size n the following inequalities hold:

$np\geq 5 \;and\;nq \geq 5$

in our case np = 200*0.85 = 170 and nq = 200*0.15 = 30

4 0

3 years ago

What's the range of the function shown below ? Thanks

Artemon [7]

Y>0 because raising a number to a negative power doesn't make it negative

5 0

2 years ago

A library database shows the total number of books checked out at any given time as a negative number. What are the possible num

Black_prince [1.1K]

Answer:

LED Lights

Step-by-step explanation:

Blue- Sad

Yellow- Happy

Red-Mad

Green-Disgusting

Purple - Scared

7 0

2 years ago

Whats the mean absolute deviation of 2 2 2 2 2 2 2 2

saveliy_v [14]

Answer:

mad is 0

Step-by-step explanation:

what type of question is this? no offense

6 0

2 years ago