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3 years ago

1/4 is 60% of x. Write a proportion that you can use to find x

Mathematics

2 answers:

hammer [34]3 years ago

7 0

0.6x = 0.25
Woooooooo

nevsk [136]3 years ago

4 0

Answers:

1/4 over x = 60/100

x= 5/12

Step-by-step explanation:

I just want to say, for everyone who was struggling with this, I was rather angry as well when the other answer did not even try to find the answer.

Have a nice day!

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Need help please. Kind of confused

muminat

What you do is look at the graph and whatever that line is on then that will be your answer.

7 0

4 years ago

Read 2 more answers

A standard american eskimo dog has a mean weight of 30 lbs with a standard deviation of 2 pounds. What is the range of weights w

Oksi-84 [34.3K]

Answer:

A and B ( page 12 and page 20 )

Step-by-step explanation:

1/4 of an hour he read 9 pages ( 15 mins ) ( 60 / 1 hour divided by 4 = 15 ) In other words 9 pages in 15 mins. To get to an hour u gotta multiply by 4. 15x4=60 9x4=36 ( 1 hour of reading is 36 pages read )

60 divided by 3 = 20

36 divided by 3 = 12 for sure it’s A and B

6 0

3 years ago

What are the roots of the quadratic equation below 2x^2+8x+7=0

Naya [18.7K]

Answer:

x = -1.29 and -2.71

Step-by-step explanation:

Use the quadratic formula, which is $x=\frac{-b+\sqrt{b^2-4ac} }{2a}$ and $x=\frac{-b-\sqrt{b^2-4ac} }{2a}$

$\frac{-8+\sqrt{8^2-4(2)(7)} }{2(2)}$ and $\frac{-8-\sqrt{8^2-4(2)(7)} }{2(2)}$

$\frac{-8+\sqrt{8} }{4}$ and $\frac{-8-\sqrt{8} }{4}$

Further reduced down to:

$\frac{-8+2\sqrt{2} }{4}$ and $\frac{-8-2\sqrt{2} }{4}$

In decimal form, to the hundredths place, both of these are:

-1.29 and -2.71

4 0

3 years ago

Question 3

bekas [8.4K]

X=w+v-k
Or
X= -k +w+v

5 0

3 years ago

Read 2 more answers

3 rays have common vertex. All the angles, which are made by neighbor rays( I think they mean adjacent rays), can be:

soldier1979 [14.2K]

Answer:

$b)\ Obtuse$

Step-by-step explanation:

$We\ are\ given\ that:\\There\ are\ three\ rays.\\Lets\ mark\ them\ Ray\ OP, OQ,\ and\ OR\ with\ their\ common\ Vertex\ O.\\\\Now,\\We\ know\ that\ the\ sum\ of\ all\ angles\ around\ a\ point[or\ here\ Vertex\ O]\\ should\ be\ equal\ to\ 360.\\Here,\\\\Lets\ consider\ each\ case\ sepearately.\\If\ all\ the\ angles\ formed: \angle POR, \angle ROQ, \angle POQ,\ are\ acute\ then:\\\angle POR, \angle ROQ, \angle POQ$

$\angle POR+ \angle ROQ+ \angle POQ$

$But\ here\ the\ sum\ of\ the\ angles\ are\ less\ than\ 270,\ but\ the\ sum\ should\\ instead\ be\ 360.\\Hence,\ the\ angles\ formed\ by\ the\ rays\ are\ NOT\ acute.$

$Similarly,\\If\ all\ the\ angles\ formed: \angle POR, \angle ROQ, \angle POQ,\ are\ right\ then:\\\angle POR, \angle ROQ, \angle POQ =90\\When\ we\ add\ them\ again:\\\angle POR+ \angle ROQ+ \angle POQ=90+90+90=270\\But\ again\ the\ sum\ here\ is\ equal\ to\ 270,\ but\ instead\ the\ sum\ had\ to\\ be\ equal\ to\ 360.\\Hence,\\The\ angles\ formed\ are\ NOT\ right.$

$Lets\ consider\ the\ Last\ Case,\\If\ the\ angles\ formed: \angle POR, \angle ROQ, \angle POQ\ are\ obtuse,\\\angle POR, \angle ROQ, \angle POQ>90\\When\ we\ add\ them:\\\angle POR+ \angle ROQ+ \angle POQ>(90+90+90)>270\\Here,\\The\ angles\ formed\ are\ greater\ than\ 270.\ As\ 360>270,\ the\ angles\ ARE\\ obtuse.$

4 0

3 years ago