Question

What are the roots of the quadratic equation below 2x^2+8x+7=0

Answer 1

Answer:

x = -1.29 and -2.71

Step-by-step explanation:

Use the quadratic formula, which is $x=\frac{-b+\sqrt{b^2-4ac} }{2a}$ and $x=\frac{-b-\sqrt{b^2-4ac} }{2a}$

$\frac{-8+\sqrt{8^2-4(2)(7)} }{2(2)}$ and $\frac{-8-\sqrt{8^2-4(2)(7)} }{2(2)}$

$\frac{-8+\sqrt{8} }{4}$ and $\frac{-8-\sqrt{8} }{4}$

Further reduced down to:

$\frac{-8+2\sqrt{2} }{4}$ and $\frac{-8-2\sqrt{2} }{4}$

In decimal form, to the hundredths place, both of these are:

-1.29 and -2.71