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Alex_Xolod [135]
3 years ago
11

The question is in the picture, please someone help me with this.

Mathematics
1 answer:
Len [333]3 years ago
8 0

Answer:

X represents time

Y represents the number of spray paint t-shirts

M = 2/1

B = 30

Equation:  y = 2/1x + 30

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Examine the diagram, where BD is tangent to circle M at point D, and BA is secant to the same circle at points E and A.
Stella [2.4K]

Answer:

19 = x

Step-by-step explanation:

The square of the tangent segment = The product of (whole secant segment) (the outside part of the secant segment)

BD²= (BA)(BE)        

8² = (4 + x - 7) (4)             BA = BE + EB

8² = (x - 3)(4)

64 = 4x - 12

64 + 12 = 4x

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3 0
2 years ago
Determine the range of the following graph
Ierofanga [76]

Given:

The graph of a function is given.

To find:

The range of the graph.

Solution:

We know that, the domain is the set of input values and range is the set of output values.

In a graph, domain is represented by the x-axis and range is represented by the y-axis.

From the given graph it is clear that there is an open circle at (-8,-8) and a closed circle at (3,4). It means the function is not defined at (-8,-8) but defined for (3,4).

The graph of the function is defined over the interval -8. So, the domain is (-8,3].

The values of the function lie in the interval -8. So, the range is (-8,4].

Therefore, the range of the function are all real values over the interval (-8,4].

7 0
3 years ago
Filipo is building a rectangular sandbox . The length of the sandbox is 1 foot longer than twice the width of the sandbox .the p
Alla [95]

Answer:

Part A : D.) 2w + 2(2w+ 1) = 29

Part B : Length of the sandbox is 10 feet.

Step-by-step explanation:

Given,

Perimeter = 29 ft

We need to find the equation for the perimeter and also the length of the sandbox.

Solution,

Let the width of the sandbox be 'w'.

Now as per question said;

The length of the sandbox is 1 foot longer than twice the width of the sandbox.

So we can say that;

Length = 2w+1

Now we know that the perimeter is equal to the sum of twice of length and width.

framing in equation form, we get;

Perimeter = 2(2w+1)+2w

we have given the perimeter, so on substituting the value, we get;

29=2(2w+1)+2w

Hence The equation used to find the width is  29=2(2w+1)+2w.

Now we solve for 'w'.

Applying distributive property, we get;

4w+2+2w=29\\\\6w+2=29

Subtracting both side by '2' we get

6w+2-2=29-2\\\\6w=27

Dividing both side by 6 we get;

\frac{6w}{6}=\frac{27}{6}\\\\w=4.5\ ft

Width of the sandbox = 4.5 ft

Length of the sandbox = 2w+1=2\times4.5 +1 = 9+1=10\ ft

Hence Length of the sandbox is 10 feet.

3 0
3 years ago
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puteri [66]
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2 years ago
The difference of 5 times y and 3
saul85 [17]
The way to find the difference between 5y - 3 you have to first do the inverse operation of multiplication which is division.

                5y - 3
                __   __
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                 y - 0.6
3 0
3 years ago
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