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irina1246 [14]
4 years ago
10

Asking again! Please solve! For both! Brainliest and lots of points!

Mathematics
2 answers:
Dennis_Churaev [7]4 years ago
8 0

Answer:

1 D (10, 120)

2 C (20, 40)

Step-by-step explanation:

charle [14.2K]4 years ago
6 0

Answer:

its what the other person said

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Algebra 1 cp
sattari [20]
The answer is 14 and 42
8 0
3 years ago
The lengths of the sides of a triangle are in the ratio of 6:6:5. The perimeter of the triangle
Oliga [24]

Hello!

Answer:

12 cm, 12 cm, 10 cm.

Step-by-step explanation:

Given:

Perimeter, or P = 34 cm

Ratio of sides = 6 : 6 : 5

To find the length of each side, we can use a variable in the ratio to find the perimeter:

34 = 6x + 6x + 5x

Combine like terms:

34 = 17x

Solve for x:

34/17 = 17x/17; x = 2

Plug in this value of "x" into each expression for the side-lengths:

6(2) = 12 cm

6(2) = 12 cm

5(2) = 10 cm

Therefore, the lengths of each side of the triangle are 12 cm, 12 cm, 10 cm.

Hope this helped you! :)

4 0
3 years ago
Read 2 more answers
A bouncy ball is dropped from a height of 16ft and always rebounds of the distance of the previous fall.
nika2105 [10]
16x5=80 cause if it bounces 16 times 5 times then
4 0
2 years ago
Read 2 more answers
Write an equation of the line that passes through (-4,1) and is perpendicular to the
trasher [3.6K]

Answer:

line1:y=2x+3

Gradient1=2

Let line2 be the line passes through (-4,1)and perpendicular to line1.

Because line2 and line1 are perpendicular, (gradient of line2) (gradient of line1) =-1

Gradient of line2=-1/2

Equation of line2:y-y1 =m(x-x1)

:y-1 =(-1/2)[x-(-4)]

:(y-1)(-2)=(x+4)

:-2y+2 =x+4

:-2y+2-x-4=0

:-x-2y-2 =0

:x+2y+2 =0

*notes:gradient=m

3 0
3 years ago
X/5-2=x/2+3 solve for x
Makovka662 [10]
Solve for x:x/5 - 2 = x/2 + 3
Put each term in x/5 - 2 over the common denominator 5: x/5 - 2 = x/5 - (10)/5:x/5 - (10)/5 = x/2 + 3
x/5 - (10)/5 = (x - 10)/5:(x - 10)/5 = x/2 + 3
Put each term in x/2 + 3 over the common denominator 2: x/2 + 3 = x/2 + 6/2:(x - 10)/5 = x/2 + 6/2
x/2 + 6/2 = (x + 6)/2:(x - 10)/5 = (x + 6)/2
Multiply both sides by 10:(10 (x - 10))/5 = (10 (x + 6))/2
10/5 = (5×2)/5 = 2:2 (x - 10) = (10 (x + 6))/2
10/2 = (2×5)/2 = 5:2 (x - 10) = 5 (x + 6)
Expand out terms of the left hand side:2 x - 20 = 5 (x + 6)
Expand out terms of the right hand side:2 x - 20 = 5 x + 30
Subtract 5 x from both sides:(2 x - 5 x) - 20 = (5 x - 5 x) + 30
2 x - 5 x = -3 x:-3 x - 20 = (5 x - 5 x) + 30
5 x - 5 x = 0:-3 x - 20 = 30
Add 20 to both sides:(20 - 20) - 3 x = 20 + 30
20 - 20 = 0:-3 x = 30 + 20
30 + 20 = 50:-3 x = 50
Divide both sides of -3 x = 50 by -3:(-3 x)/(-3) = 50/(-3)
(-3)/(-3) = 1:x = 50/(-3)
Multiply numerator and denominator of 50/(-3) by -1:Answer:  x = (-50)/3
7 0
3 years ago
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