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3 years ago

7

$4.00 + $2.00= answer

1 answer:

Mkey [24]3 years ago

4 0

Uhh $6.00 is your answer have a good day!

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Find an equation of the line containing the given pair of points (5,2) and (-3,5)

anzhelika [568]

(5,2)(-3,5)
slope = (5 - 2) / (-3 - 5) = -3/8

y = mx + b
slope(m) = -3/8
use either of ur points...(5,2)...x = 5 and y = 2
now we sub and find b, the y int
2 = -3/8(5) + b
2 = - 15/8 + b
2 + 15/8 = b
16/8 + 15/8 = b
31/8 = b

so ur equation is : y = -3/8x + 31/8....or 3x + 8y = 31

3 0

2 years ago

Bryan created a scale drawing of his rectangular bedroom. His drawing had dimensions of 6 inches by 8 inches. If the scale that

vlabodo [156]

Answer:

56 feet

Step-by-step explanation:

If 1 inch = 2 feet, we can first find the actual dimensions of his room by multiplying the number of inches by 2.

6(2)

= 12

8(2)

= 16

So, the actual dimensions of his room are 12 feet by 16 feet.

To find the perimeter, use the perimeter formula, P = 2l + 2w.

Plug in the length and width:

P = 2l + 2w

P = 2(12) + 2(16)

P = 24 + 32

P = 56

So, the perimeter of his actual room is 56 feet.

6 0

2 years ago

Use a calculator to find the square for 7.6

natita [175]

Answer:

Using a calcuator, $7.6^{2} =57.76$

6 0

2 years ago

Read 2 more answers

(5x - 1, if x < -2<br> Evaluate f(x) =<br> Lx+ 3, if x > -2<br> when z = 3.

Brilliant_brown [7]

Answer:

(5x - 1, if x < -2

Evaluate f(x) =

Lx+ 3, if x > -2

when z = 3.

Step-by-step explanation:

5 0

2 years ago

Identify the vertex, axis of symmetry, minimum or maximum, domain, and range of the function f(

alekssr [168]

Identify the vertex, axis of symmetry, minimum or maximum, domain, and range of the function ()=−(+)^−

<em><u>Answer:</u></em>

vertex = (-4, -5)

Axis of symmetry = -4

use the (-4, -5) to find the minimum value

$Domain = ( - \infty, \infty ) , [ x | x\ is\ real ]\\\\Range = [ -5, \infty ), y\geq -5$

<em><u>Solution:</u></em>

Given function is:

$f(x) = (x+4)^2 - 5$

The equation in vertex form is given as:

$y = a(x-h)^2+k$

Where, (h, k) is constant

On comparing give function with vertex form,

h = -4

k = -5

Vertex is (-4 , -5)

Axis of symmetry : x co-ordinate of vertex

Thus, axis of symmetry = -4

The coefficient of x^2 is positive in given function.

Thus the vertex point will be a minimum

$Minimum\ value = f(\frac{-b}{a})$

$f(x) = x^2 + 8x + 16 - 5\\\\f(x) = x^2 + 8x + 11$

$f(x) = ax^2+bx+c$

On comparing,

a = 1

b = 8

$x = \frac{-b}{2a} = \frac{-8}{2 \times 1} = -4$

$f(-4) = (-4)^2 + 8(-4) + 11 = 16 - 32 + 11 = -5$

Thus, use the (-4, -5) to find the minimum value

Domain and range

$f(x) = (x+4)^2 - 5$

The domain is the input values shown on the x-axis

The range is the set of possible output values f(x)

Therefore,

$Domain = ( - \infty, \infty ) , [ x | x\ is\ real ]\\\\Range = [ -5, \infty ), y\geq -5$

4 0

2 years ago