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Jet001 [13]
3 years ago
9

A tire has a radius of 20 inches. What is the Circumference of the tire?

Mathematics
1 answer:
bearhunter [10]3 years ago
7 0

Answer:

Step-by-step explanation:

circumference=2πr

=2*3.14*20

=125.6 inches

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Julie makes $9.26 an hour. this week she worked 20 hours and had $32.62 deducted for her payroll taxes what was her net income
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Net pay $152.58

9.26 times 20 - 32.62
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On a grocery store shelf, there are 16 loaves of white bread and 24 loaves of wheat bread. A shopper randomly selects a loaf of
Oksanka [162]

Answer:

60%

Step-by-step explanation:

16 loaves of white bread and 24 loaves of wheat bread. = 40 loaves of bread

P( wheat) = number of wheat/ total

                 = 24/40

                 =.6

                  =60%

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How do u know if a like is linear?
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Step-by-step explanation:

Linear means strait but what are you asking ?

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Musa invest R1000 on a simple interest at a rate of 8% per annum for 3 years.How much money will be in his account by the end of
Serjik [45]

Answer:

Step-by-step explanation:

1000*(1+8:100)^3=1000*1 ,08^3=1000*1,259712=1259,712

8 0
3 years ago
In 2008, data from the Center for Disease Control revealed that 28.5% of all male teenagers, aged 18-19 and attending U.S. colle
m_a_m_a [10]

Answer:

a) H0 : u = 28.5%

H1 : u < 28.5%

b) critical value = - 1.645

c) test statistic Z= - 1.41

d) Fail to reject H0

e) There is not enough evidence to support the professor's claim.

Step-by-step explanation:

Given:

P = 28.5% ≈ 0.285

X = 210

n = 800

p' = \frac{X}{n} = \frac{210}{800} = 0.2625

Level of significance = 0.05

a) The null and alternative hypotheses are:

H0 : u = 28.5%

H1 : u < 28.5%

b) Given a 0.05 significance level.

This is a left tailed test.

The critical value =

-Z_0.05 = -1.645

The critical value = -1.645

c) Calculating the test statistic, we have:

Z = \frac{p' - P}{\sqrt{\frac{P(1-P)}{n}}}

Z = \frac{0.2625 - 0.285}{\sqrt{\frac{28.5(1-28.5)}{800}}}

Z = -1.41

d) Decision:

We fail to reject null hypothesis H0, since Z = -1.41 is not in the rejection region, <1.645

e) There is not enough evidence to support the professor's claim that the proportion of obese male teenagers decreased.

5 0
3 years ago
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