What three consecutive integers have a sum of 48? Which means that the first number is 15, the second number is 15 + 1 and the third number is 15 + 2. Therefore, three consecutive integers that add up to 48 are 15, 16, and 17.
Multiply each cost by numbers starting from 0 then keep going until you get the same cost for each
Answer:
x1 divide 23 #15*$ because you divide
Answer:
simplified to 
Step-by-step explanation:
