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3 years ago

15

A garden store has the following miscellaneous bulbs in a basket:

1 answer:

ArbitrLikvidat [17]3 years ago

4 0

Okay. Since we know that the customer before them bought one of each type of bulb, we can subtract one bulb from each type so now, here is what the store has:

5 amaryllis

6 daffodils

3 lilies

2 tulips

Next, let’s find the probability of the customer picking an amaryllis.

We know there are 5 amaryllis, so we can put that as the numerator.

Next, we have to add up all the flowers to get the denominator.

5+6+3+2

I got 16.

So now we have 5/16

So, that is our answer! 5/16, or as a decimal 0.3125, or as a percentage 31.25%.

Hope this helps! Comment if you have any questions! :)

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Please help!!! will mark brainliest

faust18 [17]

Your answer is 7.

I subtracted 5 from 12 to find the missing number for KL that is 7.

Therefore, your answer is 7

6 0

2 years ago

Read 2 more answers

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

3 years ago

517 37/50 + 312 3/100

fgiga [73]

Answer: 829 3/4 or 829 75/100

Step-by-step explanation:

6 0

3 years ago

Nick,Sarah and Gavyn share some sweets on the ratio 6:2:1. Nick gets 30 more sweets than Gavyn. How many sweets does Sarah get?

nydimaria [60]

Answer:

12

Step-by-step explanation:

N:S:G

6:2:1

Nick gets 30 more sweets than Gavyn, therefore we can say that.

$6x=x+30\\5x=30\\x=6$

As Sarah gets twice the amount of sweets that Gavyn does.

$2(6)=12$

3 0

3 years ago

Help me out please!<br> No links please I’ll report you<br> Show work!<br> I’ll give brainiest

Jet001 [13]

Itz the second choice

4 0

3 years ago