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Strike441 [17]
3 years ago
9

Y = x + 5 2x + y = 17

Mathematics
1 answer:
larisa [96]3 years ago
8 0

Answer:

y = x + 5: x=y−5

2x + y = 17 : x=-1/2y+17/2

Step-by-step explanation:

I do not exactly know what you were asking but I just answered the questions, if that is not what you were looking for tell me so I can try and edit my answer

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I WILL GIVES BRAINLIEST!!!!
andrew-mc [135]

Answer:

3 1/3 cups

Step-by-step explanation:

one and one half dozen = 1.5 * 12 = 18 cookies


18 cookies    90 cookies

---------------- = -------------

2/3 cup          x cups

using cross products

18 * x = 2/3 * 90

18 x = 60

divide each side by 18

x = 60/18    

divide top and bottom by 6

x = 10/3

change the improper fraction to a mixed number

3 goes into 10 3 times with 1 left over

x = 3 1/3 cups


6 0
3 years ago
Which expressions are equivalent to the given expression? ​
expeople1 [14]

Answer:

It is the 2nd answer choice 4 check 5

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Dori and Malory are tracking their steps taken as a health goal. Dori leaves her house at 12:00 p.m. and walks at 50 steps per m
gladu [14]
Let n = minutes since 12:00 pm when Malory catches up to Dori.

Dori travels
(50 steps/min)*(n minutes) = 50n steps

Malory begins walking at 12:20 pm, so she walks for (n - 20) minutes. She travels
(90 steps/min)*(n - 20  min) = 90n - 1800 steps

Equate the steps traveled by Dori and Malory.
90n - 1800 = 50n
40n = 1800
n = 45 min

The time corresponding to n = 45 min is 12:45 pm

Answer: 12:45 pm

7 0
3 years ago
Which equation represents the data in this function table?
777dan777 [17]

Answer:

a

Step-by-step explanation:

because its easy

6 0
3 years ago
How to know if a function is periodic without graphing it ?
zhenek [66]
A function f(t) is periodic if there is some constant k such that f(t+k)=f(k) for all t in the domain of f(t). Then k is the "period" of f(t).

Example:

If f(x)=\sin x, then we have \sin(x+2\pi)=\sin x\cos2\pi+\cos x\sin2\pi=\sin x, and so \sin x is periodic with period 2\pi.

It gets a bit more complicated for a function like yours. We're looking for k such that

\pi\sin\left(\dfrac\pi2(t+k)\right)+1.8\cos\left(\dfrac{7\pi}5(t+k)\right)=\pi\sin\dfrac{\pi t}2+1.8\cos\dfrac{7\pi t}5

Expanding on the left, you have

\pi\sin\dfrac{\pi t}2\cos\dfrac{k\pi}2+\pi\cos\dfrac{\pi t}2\sin\dfrac{k\pi}2

and

1.8\cos\dfrac{7\pi t}5\cos\dfrac{7k\pi}5-1.8\sin\dfrac{7\pi t}5\sin\dfrac{7k\pi}5

It follows that the following must be satisfied:

\begin{cases}\cos\dfrac{k\pi}2=1\\\\\sin\dfrac{k\pi}2=0\\\\\cos\dfrac{7k\pi}5=1\\\\\sin\dfrac{7k\pi}5=0\end{cases}

The first two equations are satisfied whenever k\in\{0,\pm4,\pm8,\ldots\}, or more generally, when k=4n and n\in\mathbb Z (i.e. any multiple of 4).

The second two are satisfied whenever k\in\left\{0,\pm\dfrac{10}7,\pm\dfrac{20}7,\ldots\right\}, and more generally when k=\dfrac{10n}7 with n\in\mathbb Z (any multiple of 10/7).

It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when k is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.

Let's verify:

\sin\left(\dfrac\pi2(t+20)\right)=\sin\dfrac{\pi t}2\underbrace{\cos10\pi}_1+\cos\dfrac{\pi t}2\underbrace{\sin10\pi}_0=\sin\dfrac{\pi t}2

\cos\left(\dfrac{7\pi}5(t+20)\right)=\cos\dfrac{7\pi t}5\underbrace{\cos28\pi}_1-\sin\dfrac{7\pi t}5\underbrace{\sin28\pi}_0=\cos\dfrac{7\pi t}5

More generally, it can be shown that

f(t)=\displaystyle\sum_{i=1}^n(a_i\sin(b_it)+c_i\cos(d_it))

is periodic with period \mbox{lcm}(b_1,\ldots,b_n,d_1,\ldots,d_n).
4 0
3 years ago
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