A. (3.5, -4)
The solution is where both lines intersect
Answer:
Step-by-step explanation:
they want to know a point on the line... that has a gradient ( think slope ) of -1/3 and has the point of (-2,5) on it. So find the formula for that line
with the point slope formula y-y1 = m(x - x1)
plug in what we know
y - 5 = - 1/3 (x -(-2))
y - 5 = -1/3(x+2)
y - 5 = -1/3x - 2/3
y = - 1/3x - 2/3 + 5
y = - 1/3x + 4 1/3
y = -1/3x + 13 / 3
Now use your formula to find any new point plug in 1 for x ( b/c it's easy)
y = 12/3 when x= 1. so ( 1, 4 ) is another point on the line :)
don't forget to show your work :P
Answer:
ABCD is a parallelogram. True or False
True, opposite sides are parallel and equal
ABCD is a Rhombus. True or False
True, all sides of the shape are equal, and opposite angles are equal. The shape meets all requirements to be a Rhombus.
ABCD is a Rectangle. True or False
True, opposite sides are the same length and there are 4 right angles
Step-by-step explanation:
You will have to plot the points but here you go
Complete Question
The complete Question is attached below
Answer:
Option D
Step-by-step explanation:
From the question we are told that:
Slant asymptote of 
Vertical asymptote at 
Points (0,6)
Generally the Denominator is give as
With
Vertical Asymptote at
Therefore
Denominator = (x-1)
Generally Slant asympote 2x Gives the Coefficient of the numerator
Therefore
The expression for a rational function f(x) that satisfies the conditions
Option D
