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Andreas93 [3]
3 years ago
11

A giraffe is 16 feet tall and casts a

Mathematics
2 answers:
maxonik [38]3 years ago
6 0

Answer:

x/93/5 = 2/3

Multiplying both sides with 93/5

x = 2/3 * 93/5

x = 62/5 =12.4 feet tall

Step-by-step explanation:

Basile [38]3 years ago
5 0

how many feet does Dustin cast and i can't draw a pic

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Please help I need it asap pls pls pls
velikii [3]

Answer:

1 person = 0.75

1 person = 3/4

Step-by-step explanation:

This answer is at best a guess. It seems to me that you are constructing a circle graph, and I would like that confirmed.

The total number of people in the survey is

Total in survey = 96 + 60 + 24 + 96 + 204

Total in survey = 480

A circle contains 360 degrees.

480 people have 360 degrees of circle room

1  person has x degrees of circle room

480 / 1 = 360 / x

Cross multiply

480 x = 360 *1       Divide both sides by 480

x = 360 / 480

x = 0.75

One person takes 3/4 of a degree of the circle.

So the number of people wanting to go to the UK would be

96 * 0.75 = 72 degrees,

For each part of the table, just use what the frequency is for that entry where 96 is now.

4 0
3 years ago
Which is the surface area of the cube
leva [86]

Surface area of the cube is , I don’t know

6 0
3 years ago
Read 2 more answers
What are the zeros of the function f(x) = x2 + 8x + 4, expressed in simplest radical form? x = –4 ± 2
Katena32 [7]
It's -4 + 2 with a square root of 3.
8 0
4 years ago
Read 2 more answers
Test the claim that LeBron James and Steph Curry average the same amount of points per game, on average.
Elina [12.6K]

When the variances are known and the sample size is high, a z-test is used to assess if two population means vary. The mean of the two players is not the same.

<h3>What is a Z-test?</h3>

When the variances are known and the sample size is high, a z-test is used to assess if two population means vary.

In order to execute an appropriate z-test, the test statistic is expected to have a normal distribution, and nuisance factors such as standard deviation should be known.

(1) Null and Alternative Hypotheses

The following null and alternative hypotheses need to be tested:

\begin{array}{ccl} H_0: \mu_1 & = & \mu_2 \\\\ H_a: \mu_1 & \ne & \mu_2 \end{array}

This corresponds to a two-tailed test, and a z-test for two means, with known population standard deviations, will be used.

(2) Rejection Region

Based on the information provided, the significance level is α=0.05, and the critical value for a two-tailed test is z_c = 1.96

The rejection region for this two-tailed test is R={z:∣z∣>1.96}

(3) Test Statistics

The z-statistic is computed as follows:

\begin{array}{ccl} z & = & \displaystyle \frac{\bar X_1 - \bar X_2}{\sqrt{ {\sigma_1^2/n_1} + {\sigma_2^2/n_2} }} \\\\ & = & \displaystyle \frac{ 30.1 - 25.5}{\sqrt{ {9.112^2/70} + {12.602^2/70} }}  \\\\ & = & 2.475 \end{array}

\begin{array}{ccl} z & = & \displaystyle \frac{\bar X_1 - \bar X_2}{\sqrt{ {\sigma_1^2/n_1} + {\sigma_2^2/n_2} }} \\\\ & = & \displaystyle \frac{ 30.1 - 25.5}{\sqrt{ {9.112^2/70} + {12.602^2/70} }}  \\\\ & = & 2.475 \end{array}

(4.) The decision about the null hypothesis

Since it is observed that |z| = 2.475 > z_c = 1.96, it is then concluded that the null hypothesis is rejected.

Using the P-value approach: The p-value is p = 0.0133p=0.0133, and since p = 0.0133 < 0.05p=0.0133<0.05, it is concluded that the null hypothesis is rejected.

(5.) As it is concluded that the null hypothesis H₀ is rejected. Therefore, there is enough evidence to claim that the population mean μ1  is different than μ2.

Hence, the mean of the two players is not the same.

Learn more about Z-test:

brainly.com/question/15683598

#SPJ1

4 0
3 years ago
mat deposited $2,000.00 in the bank. if the rate of simple interest was 10%, what was the amount of money mat had in the bank af
Mekhanik [1.2K]
Principal amount of money deposited by Mat in the bank = $2000
Rate of simple interest given by the bank = 10%
Number of years for which the money is kept in the bank = 5 years
As no money was withdrawn from the account, so
Amount after 5 years = Principal [1 + (Rate * Time)]
                                  = 2000 [ 1 + (10/100) * 5]
                                  = 2000 [ 1 + (1/2)]
                                 = 2000 * (3/2)
                                 = 1000 * 3
                                 = 3000 dollars
So the amount of money made by Mat after 5 years will be $3000.00
8 0
3 years ago
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