2 years ago

Please help me giving brainliest

Mathematics

1 answer:

Gemiola [76]2 years ago

7 0

Answer:

42cm^2

3x2=6x7=42

Step-by-step explanation:

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Solve the system of linear equations.

RoseWind [281]

Answer:

1. No solution

2. Infinite solutions

Step-by-step explanation:

1. To solve the system, set the equations equal to each other and solve for x.

2x - 5 = 2x + 7

-5 = 7

This is a false statement. This means there is no solution.

2. To solve the system, graph each equation.

y = -3/4 x - 5/2 has a y-intercept -5/2 and slope -3/4.

3x + 4y = -10 converts to y = -3/4x -5/2.

This graphs as the exact same line. This system has infinite solutions.

4 0

3 years ago

Mrs. Moore has 98 pieces of candy to split among s students. Which expression shows how many pieces of candy each student will r

Nimfa-mama [501]

Answer:
I'm assuming that the s stands for 5 so it would be 19.6
Step-by-step explanation:

6 0

2 years ago

01010101010101010100101010100100101010101010010101101001010101101001010100101010101010100000000010101010101010010101010101010101

Xelga [282]

Answer:

1. first one

2. there are no solutions that i see

Step-by-step explanation:

5 0

2 years ago

One horsepower is equal to how many foot pounds of work per second

gizmo_the_mogwai [7]

I belive its 5 fpow i think

7 0

3 years ago

Read 2 more answers

The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasin

hoa [83]

Answer:

$\frac{dI}{dt}=-0.00016 A/s$

Step-by-step explanation:

We are given that

By ohm's law

$V=IR$

R=389 ohm

I=0.03 A

$\frac{dV}{dt}=-0.06V/s$

$\frac{dR}{dt}=0.07ohm/s$

We have to find rate of change of current I means $\frac{dI}{dt}$

Differentiate the equation w.r.t t

$\frac{dV}{dt}=\frac{dI}{dt}R+I\frac{dR}{dt}$

Substitute the values then we get

$-0.06=\frac{dI}{dt}\times 389+0.03\times 0.07$

$-0.06=389\frac{dI}{dt}+0.0021$

$-0.06-0.0021=389\frac{dI}{dt}$

$-0.0621=389\frac{dI}{dt}$

$\frac{dI}{dt}=\frac{-0.0621}{389}=-0.000160 A/s$

Hence, the current I is changing at the rate=-0.00016A/s

4 0

3 years ago