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4 years ago

Solve the inequality 6x - 8 > 4x + 26.

Mathematics

1 answer:

Mashutka [201]4 years ago

3 0

Answer:

the answer is x>17 I hope it helps you and next time use mathpapa

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A pilot is flying a CRJ-900 from Phoenix, Arizona, to Louisville, Kentucky. The aircraft cannot take off or land if the temperat

ioda

We need to find an inequality that represents the possible landing or take of conditions of an aircraft, the required graph and one case where the inequality will be tested.

The required inequality is $-40$ .

The graph represents the allowable temperature range in which the aircraft can takeoff or land.

The pilot could not have taken off on June 1990, the temperature in Phoenix, Arizona.

Let the temperature be denoted by $x$

The temperature cannot be at or below $-40^{\circ}\text{F}$ , so

$x>-40$

The temperature cannot be at or above $118^{\circ}\text{F}$ , so

$x$

The inequality will be $-40$ .

In the graph it can be seen that all points between -40 and 118 falls in the shaded region but it will exclude the points -40 and 118.

The graph represents the allowable temperature range in which the aircraft can takeoff or land.

The temperature in June 1990 in Phoenix, Arizona was $122^{\circ}$ which is more than $118^{\circ}\text{F}$ .

Hence, the pilot could not have taken off on this day.

Learn more:

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brainly.com/question/11612965

4 0

2 years ago

The sector COB is cut from the circle with center O. The ratio of the area of the sector removed from the whole circle to the ar

mafiozo [28]

Answer:

$Ratio = \frac{R^2 - r^2 }{ r^2}$

Step-by-step explanation:

Given

See attachment for circles

Required

Ratio of the outer sector to inner sector

The area of a sector is:

$Area = \frac{\theta}{360}\pi r^2$

For the inner circle

$r \to radius$

The sector of the inner circle has the following area

$A_1 = \frac{\theta}{360}\pi r^2$

For the whole circle

$R \to Radius$

The sector of the outer sector has the following area

$A_2 = \frac{\theta}{360}\pi (R^2 - r^2)$

So, the ratio of the outer sector to the inner sector is:

$Ratio = A_2 : A_1$

$Ratio = \frac{\theta}{360}\pi (R^2 - r^2) : \frac{\theta}{360}\pi r^2$

Cancel out common factor

$Ratio = R^2 - r^2 : r^2$

Express as fraction

$Ratio = \frac{R^2 - r^2 }{ r^2}$

6 0

3 years ago

What is the following product? Sqr5x^8y^2 sqr10x^3 sqr12y

PSYCHO15rus [73]

Step-by-step explanation:

$\sqrt{5 {x}^{8} {y}^{2} } \times \sqrt{10 {x}^{3} } \times \sqrt{12y} \\ \\ = {x}^{4} y \sqrt{5} \times x \sqrt{10x} \times 2 \sqrt{3y} \\ \\ = 2 {x}^{5} y \sqrt{5 \times 10x \times 3y} \\ \\ = 2 {x}^{5} y \sqrt{5 \times 5 \times 2x \times 3y} \\ \\ = 2 {x}^{5} y \times 5\sqrt{ 2x \times 3y} \\ \\ = 10 {x}^{5} y \sqrt{6xy} \\$

4 0

3 years ago

You are dealt a 5 card hand from a deck of 52 cards

jeyben [28]

I got 2 aces. one heart one spade. a jack of clubs a joker and a partrige in a pear tree.

8 0

4 years ago

Increase #500 in the ratio 16:10

Oxana [17]

Answer:

Answer is 900.

Step-by-step explanation:

To find:

Increase #500 in the ratio 16:10

Solution:

New Number: Old Number = 16:10

We are given the old number as 500.

Let the new number after increase = $x$

Now, using the above ratio:

 $x$ : 500 = 16:10

$\dfrac{x}{500} = \dfrac{16}{10}\\\Rightarrow x = 500 \times \dfrac{16}{10}\\\Rightarrow x = 50 \times 16\\\Rightarrow x = 900$

Therefore, the increased value of 500 in the ration 16:10 is 900.

3 0

3 years ago