We have that the workdone in stretching natural length to is mathematically given as
W=9/2lbft
<h3>Workdone in stretching natural length</h3>
Question Parameters:
- A force of 128 lb is required to hold a spring stretched 2 ft <em>beyond </em>its natural length.
- Stretching it from its natural length to 9 inches beyond its natural length
Generally the Hookes equation for the Force is mathematically given as
F=Kx
Where
3.2lb=2ft*k
Thereofore
k=16
Force becomes
f=kx
f=16x
Hence
![W=8[x^2]^{3/4}_{0}](https://tex.z-dn.net/?f=W%3D8%5Bx%5E2%5D%5E%7B3%2F4%7D_%7B0%7D)
W=9/2lbft
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Table 3 represents an arithmetic sequence.
Solution:
To find which table represents an arithmetic sequence:
In arithmetic sequence difference of each term is equal.
Table 1:
= –12 – (–6)
d = –6
= –24 – (–12)
d = –12
Here differences are not equal.
So table 1 not represents an arithmetic sequence.
Table 2:
= 9 – 7
d = 2
= 13 – 9
d = 4
Here differences are not equal.
So table 2 not represents an arithmetic sequence.
Table 3:
= 7.3 – 8.7
d = –1.4
= 5.9 – 7.3
d = –1.4
= 4.5 – 5.9
d = –1.4
= 3.1 – 4.5
d = –1.4
Here differences are equal.
So table 3 represents an arithmetic sequence.
Answer:
The answer would be 6s-54=48.
Step-by-step explanation:
In algebra, parenthesis means multiply. 6*s= 6s. 6*9=54. The answer would then be 6s-54=48.
Answer:
-1/2
Step-by-step explanation:
I'm smart
Answer:
x = 7.2
y = 10
z = 6
Step-by-step explanation:
Since ABCD ~ JKLM, therefore, the ratio of their corresponding sides would be equal. Thus:
JK/AB = KL/BC = LM/CD = JM/AD
Substitute
12/x = y/6 = 15/9 = 10/z
✔️Find x:
12/x = 15/9
12/x = 5/3
Cross multiply
x*5 = 3*12
5x = 36
x = 36/5
x = 7.2
✔️Find y:
y/6 = 15/9
y/6 = 5/3
Cross multiply
y*3 = 5*6
3y = 30
y = 30/3
y = 10
✔️Find z:
15/9 = 10/z
5/3 = 10/z
Cross multiply
5*z = 10*3
5z = 30
z = 30/5
z = 6
