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harina [27]
2 years ago
8

In the figure, if the measure of ∠8 = 72o, what's the measure of ∠14

Mathematics
1 answer:
Archy [21]2 years ago
8 0

The angle 14 is a corresponding angle.

<h3>How to find angles?</h3>

The measure of angle 8 is 72 degrees.

The measure of angle 14 can be found as follows:

∠8 ≅ ∠16 (They are corresponding angles)

Therefore,

∠8 ≅ ∠16 ≅ 14

This is because angle 16 is corresponding angle to angle 14.

Note corresponding angles are congruent.

Therefore,

∠14 = 72 degrees

Learn more about angles here: brainly.com/question/14471843

#SPJ1

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The height of a triangle is 4 in. greater than twice its base. The area of the triangle is no more than 168 in.2. Which inequali
netineya [11]

Let

x-------> the length of the base of triangle

y-------> the height of the triangle

we know that

the area of the triangle is equal to

A=\frac{1}{2}xy

in this problem we have

A \leq 168\ in^{2}

so

\frac{1}{2}xy\leq 168 --------> equation 1

y=2x+4 --------> equation 2

Substitute equation 2 in equation 1

\frac{1}{2}x[2x+4]\leq 168

x^{2}+2x \leq 168

therefore

<u>the answer is</u>

The inequality that can be used to find the possible lengths, x, of the base of the triangle is  \frac{1}{2}x[2x+4]\leq 168 or x^{2}+2x \leq 168

5 0
3 years ago
Read 2 more answers
Suzie has 672 marbles. She wants to put the marbles into 5 containers, each with the same amount. How many marbles will be in tw
Svetradugi [14.3K]

Answer:

there would be 67.2 in 2 containers

Step-by-step explanation:

if you take 672 and divide that by 5 you get 134.4 so if you take that number and divide it by 2 you would get 67.2   hope this helps

4 0
3 years ago
Prove that 1-tan^2x/1+tan^2x=2cos^2x-1​
katen-ka-za [31]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

tan x = \frac{sinx}{cosx} , sin²x + cos²x = 1

Consider the left side

\frac{1-tan^2x}{1+tan^2x}

= \frac{1-\frac{sin^2x}{cos^2x} }{1+\frac{sin^2x}{cos^2x} } ← multiply numerator/ denominator of the whole fraction by cos²x

= \frac{cos^2x-sin^2x}{cos^2x+sin^2x}

= \frac{cos^2x-sin^2x}{1}

= cos²x - sin²x

= cos²x - (1 - cos²x)

= cos²x - 1 + cos²x

= 2cos²x - 1

= right side , thus proven

3 0
4 years ago
Read 2 more answers
HELPPP ME!!! ASAP<br> PLZZZZZZZZZZ
Leviafan [203]

ANSWER:i think its C

Step-by-step explanation:

8 0
3 years ago
Question 13 please anyone ??
fomenos
Here is how to solve it:
1) isolate x for x+y=2:
     x=2-y
2)now plug this value in 3x^2-y^2=1
                 3(2-y)^2-y^2=1
simplify to get 2y^2-12y+11=0
and you get:y_1=3+ \sqrt{ \frac{7}{2} } ,y_2=3- \sqrt{ \frac{7}{2} }

3)plug these(y1,y2) values in x+y=2
and you get:<span>x_1=-1- \sqrt{ \frac{7}{2} } ,x_2=-1+ \sqrt{ \frac{7}{2} }
hope that i helped</span>
7 0
4 years ago
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