Let
x-------> the length of the base of triangle
y-------> the height of the triangle
we know that
the area of the triangle is equal to
in this problem we have
so
--------> equation 
--------> equation 
Substitute equation
in equation
![\frac{1}{2}x[2x+4]\leq 168](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dx%5B2x%2B4%5D%5Cleq%20168)

therefore
<u>the answer is</u>
The inequality that can be used to find the possible lengths, x, of the base of the triangle is
or
Answer:
there would be 67.2 in 2 containers
Step-by-step explanation:
if you take 672 and divide that by 5 you get 134.4 so if you take that number and divide it by 2 you would get 67.2 hope this helps
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identities
tan x =
, sin²x + cos²x = 1
Consider the left side

=
← multiply numerator/ denominator of the whole fraction by cos²x
= 
= 
= cos²x - sin²x
= cos²x - (1 - cos²x)
= cos²x - 1 + cos²x
= 2cos²x - 1
= right side , thus proven
ANSWER:i think its C
Step-by-step explanation:
Here is how to solve it:
1) isolate x for x+y=2:
x=2-y
2)now plug this value in 3x^2-y^2=1
3(2-y)^2-y^2=1
simplify to get 2y^2-12y+11=0
and you get:

3)plug these(y1,y2) values in x+y=2
and you get:<span>

hope that i helped</span>