2 4/5 , 2.6 , 2.3 would be your answers in descending order. From greatest to least.
Solution
write the division as a fraction = 12y^4-4y^3 - 6y^2 + 36y - 22 over y-3 multiplied by r over y-3
r ×(2y^4 - 4y^3- 16y^2 + 36y- 22) over (y-3)^2
2ry^4 - 4ry^3 - 16ry^2 + 36ry - 22r over (y-3)^2
First, we group together the terms with variables in one side by subtracting 3/2 x and 5 from both sides of the equation.
(2/3)x - (3/2)x + 5 - 5 = (3/2)x - (3/2)x - 5
(-5/6)x = -5
The value of x from the equation is 6.
I think it might be A and C
Step-by-step explanation:
Solving this equation using the quadratic formula, we get two real solutions :
1.1926 or -4.1926
Now we know the values of v , we can calculate x since x is ∛ v
![x = \sqrt[3]{1.1926} = 1.0605 \\ x = \sqrt[3]{ - 4.1926} = - 1.6125](https://tex.z-dn.net/?f=x%20%3D%20%20%5Csqrt%5B3%5D%7B1.1926%7D%20%20%3D%201.0605%20%5C%5C%20x%20%3D%20%20%5Csqrt%5B3%5D%7B%20-%204.1926%7D%20%20%3D%20%20-%201.6125)
