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nignag [31]
2 years ago
12

Explain what would happen to a figure if you transformed it using the rule(x-2,y+4). Then state whether the image would be simil

ar, congruent, both, or neither.
Mathematics
1 answer:
Serggg [28]2 years ago
3 0

Answer:

The figure would move 2 units to the left and 4 units up and the image would be congruent.

Step-by-step explanation:

If you transformed a figure using the rule (x-2, y+4).

Then the figure would move 2 units to the left (x-2) and 4 units up (x+4).

Similar figures would have the same shapes but different sizes.

Congruent figures would have the same shapes and same sizes but might be rotated.

Figures can not be both similar and congruent.

Moving the whole shape will not change the size; therefore, the figures would be congruent.

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disa [49]
Y= 10x+60 is the answer i think
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3 years ago
99PTS!!!!!!!
Ostrovityanka [42]

h(x) = 3^x – 2 will be negative  when x is less than 0

h(2) =7

g(2)=7

This is the point they are equal

g(x)> h(x) until2

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3 years ago
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an angle bisector of a triangle divides the opposite side of the triangle into segments 6 cm and 5cm long. A second side of the
rodikova [14]
There is a not so well-known theorem that solves this problem.

The theorem is stated as follows:
"Each angle bisector of a triangle divides the opposite side into segments proportional in length to the adjacent sides"  (Coxeter & Greitzer)

This means that for a triangle ABC, where angle A has a bisector AD such that D is on the side BC, then 
BD/DC=AB/AC

Here either
BD/DC=6/5=AB/AC, where  AB=6.9,  
then we solve for  AC=AB*5/6=5.75,

or

BD/DC=6/5=AB/AC, where  AC=6.9,  
then we solve for AB=AC*6/5=8.28

Hence, the longest and shortest possible lengths of the third side are
8.28 and 5.75 units respectively.

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3 years ago
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If arc CE is 125°, what is the measure of angle CDE?
Delvig [45]

Check the picture below.

7 0
2 years ago
Choose 5 cards from a full deck of 52 cards with 13values (2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A) and 4 kinds(spade, diamond, h
Delvig [45]

Answer:

a) 182 possible ways.

b) 5148 possible ways.

c) 1378 possible ways.

d) 2899 possible ways.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question, we have that:

There are 52 total cards, of which:

13 are spades.

13 are diamonds.

13 are hearts.

13 are clubs.

(a)Two-pairs: Two pairs plus another card of a different value, for example:

2 pairs of 2 from sets os 13.

1 other card, from a set of 26(whichever two cards were not chosen above). So

T = 2C_{13,2} + C_{26,1} = 2*\frac{13!}{2!11!} + \frac{26!}{1!25!} = 182

So 182 possible ways.

(b)Flush: five cards of the same suit but different values, for example:

4 combinations of 5 from a set of 13(can be all spades, all diamonds, and hearts or all clubs). So

T = 4*C_{13,5} = 4*\frac{13!}{5!8!} = 5148

So 5148 possible ways.

(c)Full house: A three of a kind and a pair, for example:

4 combinations of 3 from a set of 13(three of a kind ,c an be all possible kinds).

3 combinations of 2 from a set of 13(the pair, cant be the kind chosen for the trio, so 3 combinations). So

T = 4*C_{13,3} + 3*C_{13.2} = 4*\frac{13!}{3!10!} + 3*\frac{13!}{2!11!} = 1378

So 1378 possible ways.

(d)Four of a kind: Four cards of the same value, for example:

4 combinations of 4 from a set of 13(four of a kind, can be all spades, all diamonds, and hearts or all clubs).

1 from the remaining 39(do not involve the kind chosen above). So

T = 4*C_{13,4} + C_{39,1} = 4*\frac{13!}{4!9!} + \frac{39!}{1!38!} = 2899

So 2899 possible ways.

4 0
3 years ago
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