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alukav5142 [94]
3 years ago
6

Esther. Vida and Clair were asked to consider two different cash flows: GH¢1000 that theycould receive today and GH¢3000 that wo

uld be received 3 years from today. Esther wantedthe GH¢1000 today. Vida chose to collect GH¢3000 in 3 years, and Clair was indifferentbetween these two options. Which of the three women made the right choice? ​
Mathematics
1 answer:
xxMikexx [17]3 years ago
6 0

Answer:

The right choice is Esther's

Step-by-step explanation:

Present worth of GH¢ after 3 years is better as its present really worth may be very high than GH¢ a thousand of today. Here fee of interest is not given to compare however GH¢ 3000 after three years will be equivalent to present well worth GH¢ 1000 if charge of interest >44.5% which may be very very excessive. Thus charge of interest > 44.5% Then GH¢ 3000 payable after 3 years could be equivalent to GH¢ 1000 Hence vide has made the proper preference. If interest price >44.5%.

Then Esther's preference will he right. (thinking about time value of money).

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For every bag of trail mix the local Scout Guide troop sells,they earn $0.45. write an expression to represent this situation.
nikitadnepr [17]
T = trail mix Q= quantity (T*Q)*0.45=X X = total money earned
5 0
3 years ago
A store is having a sale where everything is discount 30% find the discount and the sales price if a customer buys an item that
uranmaximum [27]

Answer:

$255.50

Step-by-step explanation:

365 - 30% (109.50) = 255.50

6 0
2 years ago
∆ ABC is similar to ∆DEF and their areas are respectively 64cm² and 121cm². If EF = 15.4cm then find BC.​
lyudmila [28]

{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

★ ∆ ABC is similar to ∆DEF

★ Area of triangle ABC = 64cm²

★ Area of triangle DEF = 121cm²

★ Side EF = 15.4 cm

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

★ Side BC

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

Since, ∆ ABC is similar to ∆DEF

[ Whenever two traingles are similar, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. ]

\therefore \tt \boxed{  \tt \dfrac{area( \triangle \: ABC )}{area( \triangle \: DEF)} =  { \bigg(\frac{BC}{EF} \bigg)}^{2}   }

❍ <u>Putting the</u><u> values</u>, [Given by the question]

• Area of triangle ABC = 64cm²

• Area of triangle DEF = 121cm²

• Side EF = 15.4 cm

\implies  \tt  \dfrac{64   \: {cm}^{2} }{12 \:  {cm}^{2} }  =  { \bigg( \dfrac{BC}{15.4 \: cm} \bigg) }^{2}

❍ <u>By solving we get,</u>

\implies  \tt    \sqrt{\dfrac{{64 \: cm}^{2} }{ 121 \: {cm}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \sqrt{\dfrac{{(8 \: cm)}^{2} }{  {(11 \: cm)}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \dfrac{8 \: cm}{11 \: cm}    =   \dfrac{BC}{15.4 \: cm}

\implies  \tt    \dfrac{8  \: cm \times 15.4 \: cm}{11 \: cm}    =   BC

\implies  \tt    \dfrac{123.2 }{11 } cm   =   BC

\implies  \tt   \purple{  11.2 \:  cm}   =   BC

<u>Hence, BC = 11.2 cm.</u>

{\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}

★ Figure in attachment.

\rule{280pt}{2pt}

4 0
2 years ago
Help please!!! can you show me how to do this??
IrinaK [193]
\frac{3x - 2}{x^{2} - 2x - 3} - \frac{1}{x - 3} = \frac{3x  -2}{(x + 1)(x - 3)} - \frac{1}{x - 3} = \frac{3x - 2}{(x + 1)(x - 3)} - \frac{1(x + 1)}{(x + 1)(x - 3)} = \frac{3x - 2}{(x + 1)(x - 3)} - \frac{x + 1}{(x + 1)(x - 3)} = \frac{2x - 3}{(x + 1)(x - 3)}
5 0
3 years ago
Factor of 28 that will add or subact to get 3
Crazy boy [7]
4 times 7 gets 28 and 7-4 gets you 3
7 0
3 years ago
Read 2 more answers
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