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Romashka-Z-Leto [24]
3 years ago
9

For the following right triangle, find the length x

Mathematics
1 answer:
Andrews [41]3 years ago
7 0

Answer:

5\sqrt{2}

Step-by-step explanation:

https://www.symbolab.com/solver/radical-equation-calculator/sin45%3D%5Cfrac%7B5%7D%7Bx%7D

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Select the correct answer. For which quotient is x=7 an excluded value?
Lisa [10]

Answer:

\frac{7x}{x^2 - 10x + 21} / \frac{x + 7}{7}

Step-by-step explanation:

Given

See attachment

To answer this question, we start by equating the denominators of each option to 0; then, solve for x

(a):

\frac{7x}{x^2 - 10x + 21} / \frac{x + 7}{7}

This gives

\frac{7x}{x^2 - 10x + 21} * \frac{7}{x + 7}

Set the denominator to 0

(x^2 - 10x + 21)(x + 7) = 0

Solve for x

(x^2 - 7x - 3x + 21)(x + 7) = 0

Factorize:

(x(x - 7) - 3(x - 7))(x + 7) = 0

(x - 7)(x - 3)(x + 7) = 0

This implies that:

x = 7\ or\ x = 3\ or\ x = -7

From above, one of the values of x is 7.

This implies that x = 7 is an excluded value for this quotient.

<em>Other options do not need to be checked, since there is only one answer.</em>

6 0
3 years ago
What would it be I got it wrong ?
ANTONII [103]
The correct answer is the fourth choice
5 0
4 years ago
Read 2 more answers
How do you do this on the calculator?
irakobra [83]

Answer:

B) -3.464

Step-by-step explanation:

∫₀³ g'(x) cos²(2g(x) + 1) dx

Using u substitution:

u = 2g(x) + 1

du = 2g'(x) dx

½ du = g'(x) dx

When x = 0, u = 11.

When x = 3, u = -3.

½ ∫₁₁⁻³ cos²(u) du

You can use a calculator to solve this, or you can evaluate algebraically.

Use power reduction formula:

½ ∫ (½ + ½ cos(2u)) du

¼ ∫ du + ¼ ∫ cos(2u) du

¼ ∫ du + ⅛ ∫ 2 cos(2u) du

¼ u + ⅛ sin(2u) + C

Evaluating from u = 11 to u = -3:

[¼ (-3) + ⅛ sin(-6) + C] − [¼ (11) + ⅛ sin(22) + C]

-⁷/₂ + ⅛ sin(-6) − ⅛ sin(22)

−3.464

7 0
4 years ago
What is the area of this ^2
Ad libitum [116K]
<h2>Question:- Area of the given diagram</h2>

<h2>Answer :- </h2>

Divide the diagram as shown in attachment.

Now first calculate the area of the rectangle having side 1 and 12

So area = length ×breadth

Area = 1× 12 = 12 unit²

Now find the Area of the remaining triangle with sides 12,13,5 units

So

Area =  \frac{1}{2}  \times base  \times height \:

Now put the value as -> base= 5 and height= 12

Area =  \frac{1}{2}  \times base  \times height \:  \\ Area =  \frac{1}{2}  \times 5 \times 12 \\ Area =  \frac{1}{ \cancel2}  \times 5 \times  \cancel{12}^{ \:  \: 6}  \\ Area = 5 \times 6 \\ Area = 30 \: units^{2}

Now add both areas for your answer

Area{ \tiny{1}} = 12 {units}^{2}  \\ Area{ \tiny2} = 30 {units}^{2}  \\ Area{ \tiny{total}} = Area{ \tiny{1}} + Area{ \tiny{2}} \\ Area{ \tiny{total}} = 12 + 30 = 42 {units}^{2}

8 0
3 years ago
1/2n+3=6 what is the solution to this equation
nata0808 [166]

Answer:

n=6

Step-by-step explanation:

1/2 n + 3 = 6

Subtract 3 from each side

1/2 n +3-3=6-3

1/2n = 3

Multiply each side by 2

1/2 n * 2 = 3*2

n = 6

7 0
3 years ago
Read 2 more answers
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