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Westkost [7]
3 years ago
10

Describe how you could use your height and a yardstick to determine the unknown height of a flagpole.

Mathematics
1 answer:
UNO [17]3 years ago
8 0
This works when it is not close to noon
put the yardstick next to the pole
measure the shadow of the pole, call it x
measure the letngh of the shadow of the yardstick
measure the height of the yardstick

the ratio of the height of the yardstick to the shadow of the yardstick should be close to the ratio of the height of the pole to the legnth of the shadow of the pole
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HELP ME PLEASE I DONT UNDERSTAND THIS !!!
ioda

The car is speeding at a rate of 33.3mph

<h3>Speed and distance of an object</h3>

If a certain car going 60 mph can stop in 180 ft, then we can express this as:

  • 60mph = 180ft

To determine the speed for a car traveling at 100ft, we will have:

  • x = 100ft

Take the ratio of the expression

60/x = 180/100
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x = 33.3mph

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learn more on speed here: brainly.com/question/4931057

6 0
2 years ago
how much antifreeze 25% antifreeze and 50% antifreeze should be combined to give 40 gallon of 30% antifreeze?​
VARVARA [1.3K]

32 gallons of 25 % antifreeze should be combined with 8 gallons of 50 % antifreeze to get 40 gallon of 30% antifreeze

<h3><u>Solution:</u></h3>

From given,

Final mixture is 40 gallon

Let "x" be the gallon of 25 % antifreeze

Then, (40 - x) is the gallon of 50 % antifreeze

Therefore, according to question,

"x" gallons of 25 % antifreeze should be combined with (40 - x) gallons of 50 % antifreeze to get 40 gallon of 30% antifreeze

<h3><u>Therefore, we frame a equation as:</u></h3>

25 % of x + 50 % of (40 - x) = 30 % of 40

Solve for "x"

\frac{25}{100} \times x + \frac{50}{100} \times (40-x) = \frac{30}{100} \times 40\\\\0.25x + 0.5(40-x) = 12\\\\0.25x + 20 - 0.5x = 12\\\\0.25x - 0.5x = 12 - 20\\\\-0.25x = -8\\\\0.25x = 8\\\\Divide\ both\ sides\ by\ 0.25\\\\x = 32

Thus, 32 gallons of 25 % antifreeze is used

Then, (40 - x) = (40 - 32) = 8

Thus 8 gallons of 50 % antifreeze is used

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3 years ago
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