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Westkost [7]
3 years ago
10

Describe how you could use your height and a yardstick to determine the unknown height of a flagpole.

Mathematics
1 answer:
UNO [17]3 years ago
8 0
This works when it is not close to noon
put the yardstick next to the pole
measure the shadow of the pole, call it x
measure the letngh of the shadow of the yardstick
measure the height of the yardstick

the ratio of the height of the yardstick to the shadow of the yardstick should be close to the ratio of the height of the pole to the legnth of the shadow of the pole
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Solve this equation:<br> 7x - [5 + (3x - 2)] = x - (4x - 5) + (2x - 1)
Vedmedyk [2.9K]

Answer:

x = 7/5

<em>I</em><em> </em><em>hope this</em><em> </em><em>helps</em><em> </em>

Step-by-step explanation:

7x - [5 + (3x - 2)] = x - (4x - 5) + (2x - 1)

7x - 5 -3x +2 = x -4x +5 +2x -1

4x -3 = -x +4

4x +x = 4+3

5x = 7

x = 7/5

5 0
3 years ago
Liam has 5 kg of plant food. If he uses 25 g of the food on each plant, how many plants can he feed?​
bearhunter [10]

Answer:

He can feed 200 plants

Step-by-step explanation:

To solve this, we will follow the step below:

first, convert 25 g to kg

25 g = 25/1000 = 0.025 kg

Now using proportion to solve;

Let x be the number of food plant he can feed the plant

0.025 kg = 1

5 kg        = x

cross-multiply

0.025×x = 5×1

0.025x =5

Divide both-side of the equation by 0.025

0.025x/0.025 = 5/0.025

x=200  plants

Therefore, he can feed 200 plants

3 0
3 years ago
Help me please!!!!!!!!!!!!
iVinArrow [24]

Answer: 0.25g<2.50.... g<10

Step-by-step explanation: Let us say that the number of gumballs bought is represented by the variable g. In this case, the question is asking how many gumballs can be bought without surpassing the price of $2.50. We know that each gumball is $0.25, therefore the number of gumballs we buy times $0.25 has to be less than $2.50. Hence, the inequality would be 0.25g<2.50. If we were to solve this then g<2.50/0.25-----> g<10. In conclusion, the number of gumballs you can buy has to be less than 10. Thank you!

6 0
3 years ago
Please help urgent fasttt
sergeinik [125]

Answer:

  • Perimeter= l1+l2+w3+w4
  • Where l1 and l2 are equal in magnitude
  • Alike w3 and l
  • w4 are equal in magnitude
  • l= (2×w)+8
  • Plug it in to the equation

3 0
3 years ago
Line k is parallel to line l. Lines k and l are parallel. Lines m and n intersect to form 2 triangles. The top triangle has angl
larisa86 [58]

Answer:The line that is congruent to angle 4 is angle 1

hope this helped :)

6 0
3 years ago
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