3 years ago

How do you simplify X^-7?

Mathematics

1 answer:

ad-work [718]3 years ago

8 0

Answer:

below

Step-by-step explanation:

Rewrite the expression using the negative exponent rule

b ^− n =1/ b^ n . 1 x^ 7

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3 years ago

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Lelechka [254]

Answer:

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Step-by-step explanation:

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Help!!<br> What is the relationship between the corresponding angle bisectors BD and XZ?

Harrizon [31]

Answer:

XZ = 2.5 BD

Step-by-step explanation:

Comparing the two triangles,

$\frac{BD}{BC}$ = $\frac{XZ}{XY}$

$\frac{6}{8}$ = $\frac{XZ}{20}$

⇒ XZ = $\frac{20*6}{8}$

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So that,

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3 years ago

What values complete each statement?

aliya0001 [1]

For this case we have:

By properties of the radicals $\sqrt {a} = a ^{\frac {1} {2}}$

So:

$(\sqrt {7}) ^ 2 = (7 ^ {\frac {1} {2}}) ^ 2$ .

Now, for power properties we have:

$(b ^ {\frac {c} {d}}) ^ e = b ^ {\frac {c * e} {d}}$

Thus, $(7 ^ {\frac {1} {2}}) ^ 2 = 7 ^ {\frac {2} {2}} = 7$

So:

$7 ^ {\frac {1} {2}} = \sqrt {7}$ in its radical form

Answer:

$(\sqrt {7}) ^ 2 = (7 ^ {\frac {1} {2}}) ^ 2= 7 ^ {\frac {2} {2}} = 7$ in its simplest form.

$7 ^ {\frac {1} {2}} = \sqrt {7}$ in its radical form

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tino4ka555 [31]

Answer:

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Step-by-step explanation:

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