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Nata [24]
2 years ago
7

How do you find the inverse of the exponential growth function?

Mathematics
1 answer:
suter [353]2 years ago
6 0

Answer:

The inverse function of f(x) is ... f⁻¹(x) = log (x/9.16)/log (1.0054)

Step-by-step explanation:

Starting equation... f(x) = 9.16(1.0054)ˣ

Visually rewritten... y = 9.16(1.0054)ˣ

Flipping x and y... x = 9.16(1.0054)ʸ

Isolating (1.0054)ʸ... x/9.16 = (1.0054)ʸ

Taking the log of both sides... log (x/9.16) = y log (1.0054)

Isolating y... log (x/9.16)/log (1.0054) = y

Solution... y = log (x/9.16)/log (1.0054)

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Ill say true but hope its right :)
4 0
3 years ago
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It takes 1 yard 2 feet of material to make a pillow. How much material is required to make 8 pillows?
Monica [59]

40 feet or 13 yards and 1 foot

using the conversion

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7 0
3 years ago
Which graph shows a line with positive slope that passes through the point (r, s)?
Nadusha1986 [10]

r is the x coordinate and s is the y coordinate. Positive slopes go from lower left to upper right, like going up stairs or up a hill. The line that goes through (r, s) that is positive is line B.

5 0
3 years ago
What is the value of the expression shown below 10+(2x3)^2 divided by 4x (1/2)^3
stira [4]

Answer:

10 + (2 x 3)^2 / 4 x (1/2) ^3

First do the parentheses

2 x 3 = 6

1 / 2 = 0.5

We are left with

10 + 6^2 /4 x 0.5^3

Do exponents

6 x 6 = 36

0.5 x 0.5 x 0.5 = 0.125

10 + 36 / 4 x 0.125

Divide by 4 and multiply by 0.125

36 / 4 = 9

9 x 0.125 = 1.125

We are left with

10 + 1.125 = 11.125

The answer is 11.125

Step-by-step explanation:

7 0
3 years ago
Using the quadratic formula to solve x2 + 20 = 2x, what are the values of x?
jeka94

by Quadratic formula , x^2 + 20 = 2x , values of x are x = 1 \pm (1)i\sqrt{19}} . None of mentioned options are correct according to question!

<u>Step-by-step explanation:</u>

Here we have , expression  x2 + 20 = 2x or , x^2 + 20 = 2x .

We know that Quadratic formula is :

x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}

x^2 + 20 = 2x

⇒ x^2-2x+20=0

a=1\\b=-2\\c=20

Putting this value in equation x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a} :

⇒ x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}

⇒ x = \frac{-(-2) \pm \sqrt{(-2)^{2}-4(1)(20)}}{2(1)}

⇒ x = \frac{2 \pm \sqrt{4-80}}{2}

⇒ x = (\frac{2 \pm 2i\sqrt{19}}{2})

⇒ x = 1 \pm (1)i\sqrt{19}}

Therefore , by Quadratic formula , x^2 + 20 = 2x , values of x are x = 1 \pm (1)i\sqrt{19}} . None of mentioned options are correct according to question!

7 0
3 years ago
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