If you would like to solve 26/57 = 849/5x, you can do this using the following steps:
<span>26/57 = 849/5x /*(5x)
</span>26/57 * (5x) = 849 /*57
26 * 5x = 849 * 57 /26
5x = 48393/26 /5
x = <span>48393/(26*5)
x = 372.25
The correct result would be </span><span>372.25.</span><span>
</span>
Answer:
(x-7)² + (y+1)² = 4² or (x-7)² + (y+1)² =16
Step-by-step explanation:
1) coordinates of the center
x0=(x1+x2)/2=(7+7)/2=7
y0=(y1+y1)/2=(3-5)/2 = -1
(7, -1) - coordinates of the center
2) radius of the circle
length of the diameter =√((x2-x1)²+(y2-y1)²)=√((7-7)²+(-5-3)²)=√(8)²= 8
r = length of the radius = length of the diameter / 2 = 8/2 = 4
3) the equation of the circle
(x-x0)² + (y-y0)²= r²
(x-7)² + (y+1)² = 4²=16
Hey there!
This grocer is mixing two kinds of coffee. I always love the smell of coffee!
We will say that x sells for $1.15 per pound and y sells for $2.75 per pound.
Altogether there are 24 pounds of coffee he is selling.
The algebraic equation would be x + y = 24
At $1.30 per pound, he will make 24 * $1.30 = $31.2
So, how many of the x and y kinds of coffee should he use to make the $1.30 per pound mixture which will net him $31.2?
The algebraic equation would be 1.15x + 2.75y = 31.2
We now have two equations :
x+y = 24
1.15x + 2.75y = 31.2
Substituting x= 24 -y in the second equation gives us
1.15(24-y) + 2.75y = 31.2
27.6 - 1.15y + 2.75y = 31.2
27.6 + 1.6y = 31.2
1.6y = 31.2 - 27.6
0.3y= 3.6
y= 2.25
x + y = 24
x + 2.25 = 24
x = 24 -2.25
x = 21.75
If y=2.25, then x= 21.75 as well.
So, he will use 21.75 pounds of the $1.15 per/lb one and another 2.25 pounds of the $2.75per/lb one.
~Done~
The amount of degrees in a polygon: 360
In a pentagon: 360 / 5 = 72
9x - 18 = 72 Add 18 to both sides
9x = 90 Divide by 9
x = 10
Answer:
Difference between Observational and Experimental Data
The data collected in the study is observational data.
Step-by-step explanation:
In an experimental study, the data collected is divided into two groups. One group is the control group. The other group is the treatment group (also known as the experimental group). Data is gathered about the groups in order to compare their different outcomes and to draw conclusions if there is any causality based on the two variables. With observational data, the researcher is interested in observing the variables to determine if there is any correlation.
