We can factor a polynomial by finding its roots. In particular, a quadratic equation has (at most) two roots
, which would allow us to write the polynomial as

To find the solutions, we can use the quadratic formula

So, the two solutions are

And so we can factor the polynomial as follows:

Answer:
There are 13 diamond cards in a deck of cards 13 x 4 = 52 so the answer is 1/4 :)
Step-by-step explanation:
Question is Incomplete,Complete question is given below;
At a college, the cost of tuition increased by 10%. Let b be the former cost of tuition. Use the expression b + 0.10b for the new cost of tuition.
a) Write an equivalent expression by combining like terms.
b) What does your equivalent expression tell you about how to find the new cost of tuition?
Answer:
a. The equivalent expression is
.
b. The new cost of tuition is 1.1 times the former cost of tuition.
Step-by-step explanation:
Given:
Former cost of tuition = 
the cost of tuition increased by 10%.
New cost of tuition = 
Solving for part a.
we need to find the equivalent expression by combining the like terms we get;
Now Combining the like terms we get;
new cost of tuition = 
Hence The equivalent expression is
.
Solving for part b.
we need to to say about equivalent expression about how to find the new cost of tuition.
Solution:
new cost of tuition = 
So we can say that.
The new cost of tuition is 1.1 times the former cost of tuition.
Answer: 7/8 inches
Step-by-step explanation: There are 3 x's for 1/8 so that is 3/8. There are 2 x's for 1/4 which is 2/4, but you need to have the same denominator so you do 2 times the numerator and denimator which is 4/8. 3/8 + 4/8 = 7/8
5)
The summation would be (A).
We need to compare the term to its value, the first term is 2, the second term is 4, the third term is 6.
We read this as:
2(1) + 2(2) + 2(3) + 2(4) + ... + 2(10)
The zero limit would mean it would start at 0 + 2 + 4, which is not what we wanted.
6)
Like above, we read the summation notation as:
5(3) + 5(4) + 5(5) + ... + 5(8) = 15 + 20 + 25 + 30 + 35 + 40 = 3(55) = 165
9)
Repeat as above, each term of n increases by 1 as we move from 1 to 10
12)
(a) Repeat as above.
(b) We can find whether it converges or diverges by finding the common ratio.
We do this by comparing the first two terms.


We can see that the ratio will be 1/3, which is less than 1.
This information tells us that the summation will converge, thus, we can find its sum.
(c) We find the sum by using the limiting sum formula.


