Given that ∠B ≅ ∠C.
to prove that the sides AB = AC
This can be done by the method of contradiction.
If possible let AB
=AC
Then either AB>AC or AB<AC
Case i: If AB>AC, then by triangle axiom, Angle C > angle B.
But since angle C = angle B, we get AB cannot be greater than AC
Case ii: If AB<AC, then by triangle axiom, Angle C < angle B.
But since angle C = angle B, we get AB cannot be less than AC
Conclusion:
Since AB cannot be greater than AC nor less than AC, we have only one possibility. that is AB =AC
Hence if angle B = angle C it follows that
AB = AC, and AB ≅ AC.
Confusing question but I would get 0, as if you have 4cm, that squared = 16cm^2. Therefore if it were increasing anymore, then you would not be able to get a value of 16.
Answer:
12
Step-by-step explanation:
12 = 2 digits
1 + 2 = 3
1 < 2
Step-by-step explanation:
Ermm you're gonna have to write the entire question here for assistance
Answer:
I thinks its b but I don't know for sure I am taking this test too.
Step-by-step explanation: