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3 years ago

Find the distance (-4,6) and (3,-7)

Mathematics

1 answer:

forsale [732]3 years ago

3 0

Answer:

Distance ≈ 14.8

Step-by-step explanation:

Calculate the distance (d) using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 4, 6) and (x₂, y₂ ) = (3, - 7)

Hope this helps!!!!

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What is equinlents to (3-2x)(4x-7)

natali 33 [55]

Answer:

-8x^2+26x-21

Step-by-step explanation:

6 0

3 years ago

Analyze the diagram below and complete the instructions that follow. / Find the value of x. A. 4 B. 5 C. 6 D. 9

WARRIOR [948]

Answer:

Step-by-step explanation:

x^2 + (x+3)^2 = 117

x^2 + x^2+6x+9 =117

2x^2 + 6x - 108 = 0

(2x-12)(x+9)=0

x=-9,6

x cannot be negative therefore, x = 6

5 0

3 years ago

The product of (a − b)(a − b) is a2 − b2. A. Sometimes B. Always C. Never

Damm [24]

$(a-b)(a-b)=a^2-2ab+b^2\\\\a^2-2ab+b^2=a^2-b^2\\2b^2=2ab\\b^2=ab\implies a=b \vee b=0$

So, sometimes.

8 0

3 years ago

Fran is training for a cycle race. In the first week, she cycles 195 miles. In the second week, she manages 243 miles. To the ne

AleksAgata [21]

Answer:

24.6%

Step-by-step explanation:

243-195=48

48/195=x/100

48 × 100

4800/195= 24.6%

4 0

2 years ago

A grocery bag can be classified as either paper or plastic. Suppose that 85% of grocery bags are classified as plastic. (a) Tw

hjlf

Answer:

a) 0.7225

b) 0.5220

c) 0.478

It is not unusual.

Step-by-step explanation:

Probability grocery bags are plastic = 85% = 0.85

a) If two grocery bags are chosen at random, the probability that both grocery bags are plastic would be:

$^2C_2 (0.85)^2 (1-0.85)^0$

$= (0.85)^2 = 0.7225$

b) If four bags are chosen at random, the probability that all are plastic:

$^4C_4 (0.85)^4 (1-0.85)^0$

$= (0.85)^4 = 0.5220$

Probability all four bags chosen randomly are plastic bags is 0.5220

c) The probability that at least one of four randomly selected grocery bags is paper:

Let's first check for the probability of getting a paper bag.

P(paper bag) = 1 - 0.85 = 0.15

Probability of getting a paper bag is 0.15

Probability that at least one of four randomly selected grocery bags is paper would be:

$1 - ^4C_0(0.15)^0 (0. 85)^4$

$= 1 - (1)(0.85)^4$

$= 1 - 0.5220$

$= 0.478$

Since the probability that at least one bag is paper, 0.478 is greater than 0.05, it is not unusual.

3 0

3 years ago