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kvv77 [185]
2 years ago
6

I really need help on some questions can you help....​

Mathematics
1 answer:
umka2103 [35]2 years ago
3 0

Answer:

20

Step-by-step explanation:

The answer will be 20 because you are doubling from both sides.

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Passes through the points (−4, 2) and (12, 6)?
svlad2 [7]

<u>I'll assume you need to find the equation of the line that passes through those points.</u>

Answer:

\displaystyle y-2=\frac{1}{4}(x+4)

Step-by-step explanation:

<u>Equation of a Line:</u>

The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:

\displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

The given points are (-4,2) and (12,6), thus:

\displaystyle y-2=\frac{6-2}{12+4}(x+4)

Operating:

\displaystyle y-2=\frac{4}{16}(x+4)

Simplifying, the equation in point-slope form is:

\mathbf{\displaystyle y-2=\frac{1}{4}(x+4)}

3 0
2 years ago
IF you are in 5th K12 I really need help and if you know the answer them answer
ratelena [41]

Answer:

=0.013793

Step-by-step explanation:

hope i helped

3 0
3 years ago
Yoo i need help !!! its math and i havent learned it yet
BlackZzzverrR [31]

Answer:

{f}^{ - 1} (x) = 9x + 18

Step-by-step explanation:

f(x) =  \frac{1}{9}x - 2

y = \frac{1}{9} x - 2

x =  \frac{1}{9}y - 2

x + 2 =  \frac{1}{9}y

9x + 18 = y

{f}^{ - 1} (x) = 9x + 18

4 0
3 years ago
Read 2 more answers
Last two answer for both or no brainleist
professor190 [17]

Answer:

IM NOT SURE BUT DO U GO TO GEM PREP

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
If Kevin wants a 90 average in math after 5 tests and his first 4 tests are 76, 92, 89 and 97 what does he need on the fifth tes
Keith_Richards [23]
You need to understand that you're solving for the average, which you already know: 90. Since you know the values of the first three exams, and you know what your final value needs to be, just set up the problem like you would any time you're averaging something.
Solving for the average is simple:
Add up all of the exam scores and divide that number by the number of exams you took.
(87 + 88 + 92) / 3 = your average if you didn't count that fourth exam.
Since you know you have that fourth exam, just substitute it into the total value as an unknown, X:
(87 + 88 + 92 + X) / 4 = 90
Now you need to solve for X, the unknown:
87
+
88
+
92
+
X
4
(4) = 90 (4)
Multiplying for four on each side cancels out the fraction.
So now you have:
87 + 88 + 92 + X = 360
This can be simplified as:
267 + X = 360
Negating the 267 on each side will isolate the X value, and give you your final answer:
X = 93
Now that you have an answer, ask yourself, "does it make sense?"
I say that it does, because there were two tests that were below average, and one that was just slightly above average. So, it makes sense that you'd want to have a higher-ish test score on the fourth exam.
4 0
3 years ago
Read 2 more answers
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