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3 years ago

I really need help on some questions can you help....

Mathematics

1 answer:

umka2103 [35]3 years ago

3 0

Answer:

Step-by-step explanation:

The answer will be 20 because you are doubling from both sides.

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Are the polygons similar? If they are, choose the correct similarity statement and scale factor. Not drawn to scale.

Dvinal [7]

Option B: $\Delta R S T \sim \Delta UV W ; \frac{5}{6}$

Explanation:

The polygons are similar because in $\Delta R S T$ , the measure of ∠R=32°

Also, in $\Delta U V W$ , the measure of ∠U=32°

Now, we shall find the scale factor,

Since, $\Delta R S T \sim \Delta U V W$ , then the sides are proportional which is given by,

$\frac{RS}{UV}$

Substituting the values of RS and UV from the figure, we get,

$\frac{10}{12}$

Simplifying, we have,

$\frac{5}{6}$

Thus, the scale factor is $\frac{5}{6}$

Hence, Option B is the correct answer.

8 0

4 years ago

Given the data in the chart above, which statement explains why these three countries would benefit from specialization and trad

zysi [14]

B. because no one country has a distinct advantage over the others

5 0

4 years ago

Line CD contains points A (4, −7) and B (4, 8). The slope of line CD is

Fofino [41]

Answer:

Undefined

Step-by-step explanation:

Slope of CD

$= \frac{8 - ( - 7)}{4 - 4} = \frac{8 + 7}{0} = \infty \\$

Hence, Slope of CD is undefined.

4 0

3 years ago

HELP PLEASE AND THX<br> What's the slope

lara [203]

Answer:

what's the slope of what

Step-by-step explanation:

Send a pic or something.

4 0

3 years ago

Read 2 more answers

The coordinates of the vertices of ∆PQR are P(-2,5), Q(-1,1), and R(7,3). Determine whether ∆PQR is a right triangle. Show your

Mashutka [201]

Given

∆PQR points are P(-2,5), Q(-1,1), and R(7,3)

Determine whether ∆PQR is a right triangle

To proof

As given ∆PQR points are P(-2,5), Q(-1,1), and R(7,3)

First find out the sides of triangle

FORMULA

Distance formula between two points

$D^{2}= (x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}$

Distance between two points P(-2,5) and Q(-1,1)

$PR = \sqrt{(-1+2)^{2}+(1-5)^{2} }$

$PR = \sqrt{17}$

Distance between two points Q(-1,1)and R(7,3)

$QR = \sqrt{(7+1)^{2} +(3-1)^{2} }$

$QR =\sqrt{68}$

Distance between two points R(7,3) and P(-2,5)

$RP =\sqrt{(-2-7)^{2} + (5-3)^{2} }$

$RP=\sqrt{85}$

now show that ∆PQR is a right triangle

$RP^{2} = PQ^{2} +QR^{2}$

Putting the value given above

$(\sqrt{85}) ^{2} = \sqrt{17} ^{2} +\sqrt{68} ^{2}$

85 = 17 +68

85 =85

In the right triangle

HYPOTENUSE² = BASE² + PERPENDICULAR²

This is prove above

Hence ∆PQR is a right triangle

Hence proved

7 0

4 years ago

I really need help on some questions can you help....​

I really need help on some questions can you help....