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Alborosie
3 years ago
6

PLEASE HELP y= 1/2 x - 3

Mathematics
1 answer:
Westkost [7]3 years ago
3 0
Plz help I’m getting timed
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Mrs. Lay's Instagram followers went from<br> 40 to 72. What was the percent increase?
anastassius [24]

<u>Answer:  </u>

The percentage increase when Mrs.Lay’s instagram followers went from 40 to 72 is 80%

<u>Solution:</u>

The percentage increase can be found out by dividing change in value by initial value. This is given as,

\bold{\text { percentage increase } = \frac{( \text {final count-initial count} }{\text {initial count}} \times 100}

From question, we get

Initial count of Mrs.Lay = 40

Final value of Mrs.Lay = 72

So percentage increase when Mrs Lay’s Instagram followers went from 40 to 72 is

\text { percentage increase }=\frac{72-40}{40} \times 100= \frac{32}{40} \times 100

=\frac{4}{5} \times 100

= 80  

Hence percentage increase when Mrs Lay’s Instagram followers went from 40 to 72 is 80%.

4 0
3 years ago
A machine can print 300 posters in 10 minutes. How many posters can the machine print in 2 minutes?
olganol [36]

Answer: 60

Step-by-step explanation:

30 papers every minute.

3 0
3 years ago
Read 2 more answers
Abe is trying to figure out how much money he spent on gifts for his friends. Below is a list of the amounts he spent on each fr
Sindrei [870]
The answer is c 25.05

3 0
3 years ago
Five computer program modules are ranked as M1, M2, M3, M4, and M5 according to the ascending order of effort required to debug
gulaghasi [49]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

Technician selects three out of 5 systems  

In C(5,3)=10ways, this can be achieved  

In part a:

Space sample chooses 3 of a 5 systems  

(M_1, \ M_2,\ M_3),(M_1,M_2,M_4) \ (M_1,M_2,M_5) \ (M_1,M_3,M_4) \ (M_1,M_3,M_5),(M_1,M_4,M_5) \ (M_2,M_3,M_4)\ (M_2,M_3,M_5) \ (M_2,M_4,M_5),(M_3,M_4,M_5)}

In point b:

A =MODULE WHICH INCLUDE M1 minimal amount of effort  

Outcomes probable =

(M_1,M_2,M_3),\ (M_1,M_2,M_4) \ (M_1,M_2,M_5)\ (M_1,M_3,M_4)\\\\(M_1,M_3,M_5),\ (M_1,M_4,M)5)\ =\ 6

\to p(A)=\frac{6}{10}\\\\

            =0.6

In point c:

B = highest effort that is M_5

Potential result=

(M_1,M_2,M_5) \ (M_1,M_3,M_5) \ (M_2,M_3,M_5)\(M_2,M_4,M_5) \\ (M_2,M_4,M_5), \ (M_3,M_4,M_5) \ =\ 6  \\\\

\to B= \frac{6}{10} \\\\

        =0.6

\to P(B)=10

In point d:

\to \ A  \ intersection \ B=(M_1,M_2,M_5), \ (M_1,M_3,M_5) \ ,(M_1,M_4,M_5)

\to A (A \ intersection \ B) = \frac{3}{10} \\\\\ \ \ \ \ \

                                      =0.3

In point e:

\to (A \cup B) =  (M_1,M_2,M_3),\ (M_1,M_2,M_4)\ (M_1,M_2,M_5)(M_1,M_3,M_4)\ (M_1,M_3,M_5), \\ (M_1,M_4,M_5)\ (M_2,M_3,M_5) \ (M_2,M_4,M_5),(M_3,M_4,M_5) \ = \ 9\to P(A \cap B)=\frac{9}{10}

                    = 0.9

In point f:

\to (A\cap B) = \frac{3}{10}

                 = 0.3

In point g:

\to (A \cup B) = \frac{7}{10}

                 =0.7

In point h:

\to p(A \cap B) = 0.3 \neq 0

8 0
3 years ago
Helpp with this math.
Annette [7]

Answer:

it's c lol

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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