PLEASE HELP y= 1/2 x

Mrs. Lay's Instagram followers went from 40 to 72. What was the percent increase?

anastassius [24]

Answer:

The percentage increase when Mrs.Lay’s instagram followers went from 40 to 72 is 80%

Solution:

The percentage increase can be found out by dividing change in value by initial value. This is given as,

$\bold{\text { percentage increase } = \frac{( \text {final count-initial count} }{\text {initial count}} \times 100}$

From question, we get

Initial count of Mrs.Lay = 40

Final value of Mrs.Lay = 72

So percentage increase when Mrs Lay’s Instagram followers went from 40 to 72 is

$\text { percentage increase }=\frac{72-40}{40} \times 100$ $= \frac{32}{40} \times 100$

$=\frac{4}{5} \times 100$

= 80

Hence percentage increase when Mrs Lay’s Instagram followers went from 40 to 72 is 80%.

4 0

3 years ago

A machine can print 300 posters in 10 minutes. How many posters can the machine print in 2 minutes?

olganol [36]

Answer: 60

Step-by-step explanation:

30 papers every minute.

3 0

3 years ago

Read 2 more answers

Abe is trying to figure out how much money he spent on gifts for his friends. Below is a list of the amounts he spent on each fr

Sindrei [870]

The answer is c 25.05

3 0

3 years ago

Five computer program modules are ranked as M1, M2, M3, M4, and M5 according to the ascending order of effort required to debug

gulaghasi [49]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

Technician selects three out of 5 systems

In C(5,3)=10ways, this can be achieved

In part a:

Space sample chooses 3 of a 5 systems

$(M_1, \ M_2,\ M_3),$ $(M_1,M_2,M_4) \ (M_1,M_2,M_5) \ (M_1,M_3,M_4) \ (M_1,M_3,M_5),$ $(M_1,M_4,M_5) \ (M_2,M_3,M_4)\ (M_2,M_3,M_5) \ (M_2,M_4,M_5),(M_3,M_4,M_5)}$

In point b:

A =MODULE WHICH INCLUDE M1 minimal amount of effort

Outcomes probable =

$(M_1,M_2,M_3),\ (M_1,M_2,M_4) \ (M_1,M_2,M_5)\ (M_1,M_3,M_4)\\\\(M_1,M_3,M_5),\ (M_1,M_4,M)5)\ =\ 6$

$\to p(A)=\frac{6}{10}\\\\$

$=0.6$

In point c:

B = highest effort that is $M_5$

Potential result=

$(M_1,M_2,M_5) \ (M_1,M_3,M_5) \ (M_2,M_3,M_5)\(M_2,M_4,M_5) \\ (M_2,M_4,M_5), \ (M_3,M_4,M_5) \ =\ 6 \\\\$

$\to B= \frac{6}{10} \\\\$

$=0.6$

$\to P(B)=10$

In point d:

$\to \ A \ intersection \ B=(M_1,M_2,M_5), \ (M_1,M_3,M_5) \ ,(M_1,M_4,M_5)$

$\to A (A \ intersection \ B) = \frac{3}{10} \\\\\ \ \ \ \ \$

$=0.3$

In point e:

$\to (A \cup B) = (M_1,M_2,M_3),\ (M_1,M_2,M_4)\ (M_1,M_2,M_5)(M_1,M_3,M_4)\ (M_1,M_3,M_5), \\ (M_1,M_4,M_5)\ (M_2,M_3,M_5) \ (M_2,M_4,M_5),(M_3,M_4,M_5) \ = \ 9$ $\to P(A \cap B)=\frac{9}{10}$