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3 years ago

5

Which of the following expression(s) are fourth-degree trinomials? Select all that apply.

1 answer:

frozen [14]3 years ago

6 0

Answer:

Options A and B are polynomial of the fourth degree

Step-by-step explanation:

In this problem, option

A. 3x2y + 5x3y + 6y4

Is a Polynomial of the fourth degree because of the 6y⁴ term which is the highest degree

Also the option

B. 6y4 + 5x3 + 1 has a 6y⁴ term which indicates that the polynomial is a fourth degree polynomial

What is the degree of a polynomial?

In mathematics, the degree of a polynomial is the highest of the degrees of the polynomial's monomials with non-zero coefficients. The degree of a term is the sum of the exponents of the variables that appear in it, and thus is a non-negative integer

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Given sinx= −3/5 when 3π/2 < x < 2π, find tan x/2

GarryVolchara [31]

Answer:

B -⅓

Step-by-step explanation:

sinx = -3/5

Adjacent² = 5² - 3² = 16

Adjacent = 4

tan(x) = -3/4

-¾ = 2tan(½x)/[1 - tan²(½x)]

-3 + 3tan²(½x) = 8tan(½x)

3tan²(½x) - 8tan(½x) - 3 = 0

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5 0

3 years ago

Read 2 more answers

Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4

gtnhenbr [62]

Answer:

Simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

Step-by-step explanation:

We need to simplify the expression $(6^{-2})(3^{-3})(3*6)^4$

Solving:

$(6^{-2})(3^{-3})(3*6)^4$

Applying exponent rule: $a^{-m}=\frac{1}{a^m}$

$=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\$

Factors of $18=2\times 3\times 3=2\times3^2$

Factors of $6=2\times 3$

Replacing terms with factors

$=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\$

Using exponent rule: $(a^m)^n=a^{m\times n}$

$=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}$

Using exponent rule: $a^m.a^n=a^{m+n}$

$=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}$

Now using exponent rule: $\frac{a^m}{a^n}=a^{m-n}$

$=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108$

So, simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

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saul85 [17]

Answer:

Step-by-step explanation:

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crimeas [40]

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3 years ago