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2 years ago

Plz help! I really need this!

Mathematics

1 answer:

Elan Coil [88]2 years ago

3 0

Answer:

x=16

Step-by-step explanation:

the remaining angle for thw triangle is found by subtracting the already shown angles from 180 (the angle some of a triangle) which happens to be 96 to get 84 but now you need to subtract 84 from 180 to find the angle on the other side of line because lines have a total angle measurement of 180 but we already kbow what this get's us because it's 96 now we devide 96 by 6 to get 16 our answer.

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Evaluate C_n.xP^xQn-x For the given n=7, x=2, p=1/2

r-ruslan [8.4K]

Answer:

The value of given expression is $\frac{21}{128}$ .

Step-by-step explanation:

Given information: n=7, x=2, p=1/2

$q=1-p=1-\frac{1}{2}=\frac{1}{2}$

The given expression is

$C(n,x)p^xq^{n-x}$

It can be written as

$^nC_xp^xq^{n-x}$

Substitute n=7, x=2, p=1/2 and q=1/2 in the above formula.

$^7C_2(\frac{1}{2})^2(\frac{1}{2})^{7-2}$

$\frac{7!}{2!(7-2)!}(\frac{1}{2})^2(\frac{1}{2})^{5}$

$\frac{7!}{2!5!}(\frac{1}{2})^{2+5}$

$\frac{7\times 6\times 5!}{2\times 5!}(\frac{1}{2})^{2+5}$

$21(\frac{1}{2})^{7}$

$\frac{21}{128}$

Therefore the value of given expression is $\frac{21}{128}$ .

7 0

2 years ago

4.185 divided by 0.93 rounded

mr Goodwill [35]

To the nearest whole: 4
to the nearest hundredth: 4.2
actual answer: 4.5

4 0

2 years ago

Edgar owns 234 shares of Cawh Consolidated Bank, which he bought for $21.38 apiece. Each share pays a yearly dividend of $3.15.

trapecia [35]

Answer: B. The stocks have a yield 6.84 percentage points greater than that of the bonds.

Step-by-step explanation:

Firstly, the yield for stocks will be calculated as:

= return/ investment cost

= $3.15/$ 21.38

= 0.14733395

= 14.73%

The yield for bonds will be calculated as:

= Return/Investment cost

Return = 1,000 x 8.3% = 83

Investment cost = 1,000 x 105.166/100 = 1051.66‬

Yield = 83/1051.66

= 0.07892284

= 7.89%

Then, the difference between the yield will be:

= 14.73% - 7.89%

= 6.84%

Therefore, the stocks have a yield 6.84 percentage points greater than that of the bonds.

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2 years ago

If $10,500 is deposited in a compound interest account paying 2.99% interest annually, how much will be in the account after 5 y

algol [13]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10500\\ r=rate\to 2.99\%\to \frac{2.99}{100}\dotfill &0.0299\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases} \\\\\\ A=10500\left(1+\frac{0.0299}{1}\right)^{1\cdot 5}\implies A=10500(1.0299)^5\implies A\approx 12166.47$

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2 years ago

Solve the formula for the specified variable.<br> g=th for t<br> T=?

Sidana [21]

Hope this helps
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