Question

Is there anything after 16a+20 ?

Answer 1

Answer:

The equivalent expressions are:

$4\left(4a+5\right)=16a+20$

                $=2\left(8a+10\right)$

                $=12a+20+4a$  

Yes, 16a+20 could be further reduced by taking 2 as a common factor.

i.e. 16a+20 = 2(8a+10)

Step-by-step explanation:

Given the expression

• $4(4a+5)$

solving the expression to determine the equivalent expression

$4\left(4a+5\right)$

$\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac$

$4\left(4a+5\right)=4\cdot \:\:4a+4\cdot \:\:5$

                $=16a+20$

Taking 2 as the common factor

                $=2\left(8a+10\right)$

Also

$12a+20+4a = 16a+20$  

             

Therefore, the equivalent expressions are:

$4\left(4a+5\right)=16a+20$

                $=2\left(8a+10\right)$

                $=12a+20+4a$  

Yes, 16a+20 could be further reduced by taking 2 as a common factor.

i.e. 16a+20 = 2(8a+10)