What is anime? i am confused

A rectangle is 14 ft longer than its width. The perimeter is 88ft. Please help

nirvana33 [79]

Answer:

L=29ft

W=15ft

Step-by-step explanation:

Step one:

given

let the width be x

W=x

L= x+14

P= 88ft

perimeter= 2L+2W

so, substituting our data we have

88=2(x+14)+2x

88=2x+28+2x

collect like terms

88=4x+28

88-28=4x

60=4x

divide both sides by 4

x=60/4

x=15

Step two:

the dimensions are

the width is 15ft

the length= 15+14

L=29ft

8 0

3 years ago

Simplify the expression 1+2*[(3+1)*5+3]

Lady bird [3.3K]

1 + 2 *[(3+1)*5+3]

= 1 + 2*[(4)*5+3]

= 1 + 2*[20+3]

= 1 + 2 * 23

= 1 + 46

= 47

Answer

c. 47

7 0

3 years ago

Read 2 more answers

Determine whether the system of equations has no solution, one solution, or infinitely many solutions

Vinil7 [7]

Answer:

one solution

Step-by-step explanation:

y=-3x+5

y=1/2x-2

You can tell straight off the bat, it does have a solution, and it isn't infinite solutions. If it had no solution, it would have the same slope but different y-intercepts. If it had infinite solutions, the 2 equations would have to be the exact same. So there is only one solution.

---

hope it helps

4 0

3 years ago

Can someone tell me what x equals

Troyanec [42]

X=22. The supplementary angle is 90°, so the 66° angle, plus (x+2) has to add up to 90° too.

4 0

3 years ago

Solve using law of sines or law of cosines!

malfutka [58]

Answer:

Part 5) The length of the ski lift is $1.15\ miles$

Part 6) The height of the tree is 18.12 m

Step-by-step explanation:

Part 5)

Let

A -----> Beginning of the ski lift

B -----> Top of the mountain

C -----> Base of mountain

we have

$b=0.75\ miles$

$A=20\°$

$C=180\°-50\°=130\°$ ----> by supplementary angles

Find the measure of angle B

Remember that the sum of the interior angles must be equal to 180 degrees

$B=180\°-A-C$

substitute

$B=180\°-20\°-130\°=30\°$

Applying the law of sines

$\frac{b}{sin(B)}=\frac{c}{sin(C)}$

substitute

$\frac{0.75}{sin(30\°)}=\frac{c}{sin(130\°)}$

$c=\frac{0.75}{sin(30\°)}(sin(130\°))$

$c=1.15\ miles$

Par 6)

see the attached figure with letters to better understand the problem

Applying the law of sines in the right triangle BDC

In the right triangle BDC 20 degrees is the complement of 70 degrees

$\frac{BC}{sin(70\°)}=\frac{x}{sin(20\°)}$

$BC=(sin(70\°))\frac{x}{sin(20\°)}$ -----> equation A

Applying the law of sines in the right triangle ABC

In the right triangle ABC 50 degrees is the complement of 40 degrees

$\frac{BC}{sin(40\°)}=\frac{x+15}{sin(50\°)}$

$BC=(sin(40\°))\frac{x+15}{sin(50\°)}$ -----> equation B

Equate equation A and equation B and solve for x

$(sin(70\°))\frac{x}{sin(20\°)}=(sin(40\°))\frac{x+15}{sin(50\°)}\\\\2.7475x=0.8391(x+15)\\\\2.7475x=0.8391x+12.5865\\\\2.7475x-0.8391x=12.5865\\\\x=6.60\ m$

Find the value of BC

$BC=(sin(70\°))\frac{6.6}{sin(20\°)}$

$BC=18.12\ m$

therefore

The height of the tree is 18.12 m

5 0

4 years ago