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3 years ago

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The test results for 4 students are: 96, 83, 78, and 83. If one more student's test score of 87 is added, what would increase?

1 answer:

eimsori [14]3 years ago

7 0

Answer:

b

Step-by-step explanation:

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joja [24]

Part (1) : The solution is $729$

Part (2): The solution is $\frac{1}{16 x^{8}}$

Part (3): The solution is $\frac{2 x^{2}}{3 y z^{7}}$

Explanation:

Part (1): The expression is $3^{2} \cdot3^{4}$

Applying the exponent rule, $a^{b} \cdot a^{c}=a^{b+c}$ , we get,

$3^{2} \cdot 3^{4}=3^{2+4}$

Adding the exponent, we get,

$3^{2} \cdot3^{4}=3^6=729$

Thus, the simplified value of the expression is $729$

Part (2): The expression is $\left(2 x^{2}\right)^{-4}$

Applying the exponent rule, $a^{-b}=\frac{1}{a^{b}}$ , we have,

$\left(2 x^{2}\right)^{-4}=\frac{1}{\left(2 x^{2}\right)^{4}}$

Simplifying the expression, we have,

$\frac{1}{2^4x^8}$

Thus, we have,

$\frac{1}{16 x^{8}}$

Thus, the value of the expression is $\frac{1}{16 x^{8}}$

Part (3): The expression is $\frac{2 x^{4} y^{-4} z^{-3}}{3 x^{2} y^{-3} z^{4}}$

Applying the exponent rule, $\frac{x^{a}}{x^{b}}=x^{a-b}$ , we have,

$\frac{2x^{4-2}y^{-4+3}z^{-3-4}}{3}$

Adding the powers, we get,

$\frac{2x^{2}y^{-1}z^{-7}}{3}$

Applying the exponent rule, $a^{-b}=\frac{1}{a^{b}}$ , we have,

$\frac{2 x^{2}}{3 y z^{7}}$

Thus, the value of the expression is $\frac{2 x^{2}}{3 y z^{7}}$

8 0

4 years ago

Please help please help please helppppppppppppppppppp

Amiraneli [1.4K]

Answer:

600

Step-by-step explanation:

3 0

3 years ago

Maria is saving money so she can go to a professional football game. Maria has $25. She saves $5 a week.

slava [35]

Just dot upward every week because she saves $5 till you hit $70 in 9 more weeks.!!

7 0

3 years ago

Read 2 more answers

What is the GCF for # 2 <br><br> 2) 2x^2 -20x+32

ioda

so the answer is 2 for the question?

3 0

3 years ago

Find the common ratio 24,18,37/2,81/8

Vinil7 [7]

Note: The third term of the sequence should be $\dfrac{27}{2}$ instead of $\dfrac{37}{2}$ , otherwise the sequence has no common ratio.

Given:

The given sequence is

$24,18,\dfrac{27}{2},\dfrac{81}{8}$

To find:

The common ratio of the given sequence.

Solution:

The quotient of each pair of consecutive terms are:

$\dfrac{18}{24}=\dfrac{3}{4}$

Similarly,

$\dfrac{\dfrac{27}{2}}{18}=\dfrac{27}{36}$

$\dfrac{\dfrac{27}{2}}{18}=\dfrac{3}{4}$

And,

$\dfrac{\dfrac{81}{8}}{\dfrac{27}{2}}=\dfrac{81}{8}\times \dfrac{2}{27}$

$\dfrac{\dfrac{81}{8}}{\dfrac{27}{2}}=\dfrac{3}{4}$

Therefore, the common ratio of the given sequence is $\dfrac{3}{4}$ or 0.75.

8 0

3 years ago