All categories

3 years ago

Syme SUVGraph both lines on the same coordinate plane.4y = x + 8y+3 = 2 x

Mathematics

1 answer:

lapo4ka [179]3 years ago

3 0

Answer:

i can show you how to do it...

Step-by-step explanation:

first put 4y=y+3

then put x+8=2x

all you have to do is subtract 4 on both sides and also 2 on both sides

You might be interested in

What's 2 + 1 ? this thing is making me type 20 words

BaLLatris [955]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Please help!!!

irga5000 [103]

Answer:c

Step-by-step explanation:

5 0

3 years ago

Check whether the relation R on the set S = {1, 2, 3} is an equivalent

kozerog [31]

Answer:

$R$ isn't an equivalence relation. It is reflexive but neither symmetric nor transitive.

Step-by-step explanation:

Let $S$ denote a set of elements. $S \times S$ would denote the set of all ordered pairs of elements of $S\!$ .

For example, with $S = \lbrace 1,\, 2,\, 3 \rbrace$ , $(3,\, 2)$ and $(2,\, 3)$ are both members of $S \times S$ . However, $(3,\, 2) \ne (2,\, 3)$ because the pairs are ordered.

A relation $R$ on $S\!$ is a subset of $S \times S$ . For any two elements $a,\, b \in S$ , $a \sim b$ if and only if the ordered pair $(a,\, b)$ is in $R\!$ .

A relation $R$ on set $S$ is an equivalence relation if it satisfies the following:

Reflexivity: for any $a \in S$ , the relation $R$ needs to ensure that $a \sim a$ (that is: $(a,\, a) \in R$ .)

Symmetry: for any $a,\, b \in S$ , $a \sim b$ if and only if $b \sim a$ . In other words, either both $(a,\, b)$ and $(b,\, a)$ are in $R$ , or neither is in $R\!$ .

Transitivity: for any $a,\, b,\, c \in S$ , if $a \sim b$ and $b \sim c$ , then $a \sim c$ . In other words, if $(a,\, b)$ and $(b,\, c)$ are both in $R$ , then $(a,\, c)$ also needs to be in $R\!$ .

The relation $R$ (on $S = \lbrace 1,\, 2,\, 3 \rbrace$ ) in this question is indeed reflexive. $(1,\, 1)$ , $(2,\, 2)$ , and $(3,\, 3)$ (one pair for each element of $S$ ) are all elements of $R\!$ .

$R$ isn't symmetric. $(2,\, 3) \in R$ but $(3,\, 2) \not \in R$ (the pairs in $\! R$ are all ordered.) In other words, $3$ isn't equivalent to $2$ under $R\!$ even though $2 \sim 3$ .

Neither is $R$ transitive. $(3,\, 1) \in R$ and $(1,\, 2) \in R$ . However, $(3,\, 2) \not \in R$ . In other words, under relation $R\!$ , $3 \sim 1$ and $1 \sim 2$ does not imply $3 \sim 2$ .

3 0

3 years ago

Solve 10/y = 5/2 The solution is y=_

kolezko [41]

Answer:

y is equal to 4.

Step-by-step explanation:

To find this, cross multiply and then divide.

10*2 = y*5

20 = 5y

4 = y

5 0

3 years ago

What value of x makes the equation true? 3(4x-5)-4x+1=-6 Please show work

V125BC [204]

Answer:

x = 1

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Step-by-step explanation:

Step 1: Define Equation

3(4x - 5) - 4x + 1 = -6

Step 2: Solve for x

Distribute 3: 12x - 15 - 4x + 1 = -6
Combine like terms: 8x - 14 = -6
Isolate x term: 8x = 8
Isolate x: x = 1

Step 3: Check

Plug in x into the original equation to verify it's a solution.

Substitute in x: 3(4(1) - 5) - 4(1) + 1 = -6
Multiply: 3(4 - 5) - 4 + 1 = -6
Subtract: 3(-1) - 4 + 1 = -6
Multiply: -3 - 4 + 1 = -6
Subtract: -7 + 1 = -6
Add: -6 = -6

Here we see that -6 does indeed equal -6.

∴ x = 1 is the solution to the equation.

3 0

2 years ago

Syme SUVGraph both lines on the same coordinate plane.4y = x + 8y+3 = 2 x​

Syme SUVGraph both lines on the same coordinate plane.4y = x + 8y+3 = 2 x