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2 years ago

How do I work this problem out? S= 2(lw+ lh+ wh)

1 answer:

7 0

First, and most important, you must know what the question is. You haven't told us what the question is, and a gray cloud hangs like a dark mist over the problem, giving the unmistakable impression that you're not too sure of it yourself.

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Look at the picture please help

morpeh [17]

Answer:

Step-by-step explanation:

First off, we know that (g ° f)(2) is just both functions done in a ordered fashion. In this case, f(x) is done first.

To figure out what f(2) is, all we have to do is find where x = 2 is on the graph. In this case it is on point (2, 3). The input is the x and the output is the y, so f(2) = 3.

Then, we can figure out what g(3) by locating x = 3 on line g. It shows the point (3, 0). This means that g(3) = 0.

3 0

1 year ago

The graph shows one of the linear equations for a system of equations. Which equation represents the second linear equation for

bagirrra123 [75]

I think the answer is c

3 0

3 years ago

Briley has 347 marbles. Joey has 4 times as many as Briley. Carson has 799 fewer than Joey. How many marbles does Carson have?

Nadya [2.5K]

Answer:

697 marbles

Step-by-step explanation:

We know:

Briley- 374 marbles

Joey- 374*4

Carson- (374*4)-799

Solve:

374*4= 1496 (This is how many Joey has)

1496-799= 697 (This is how many Carson has)

Hope this helps!

6 0

2 years ago

In the crown Court who decides who is guilty

ehidna [41]

Answer:

The

he district judge or jury will.

6 0

2 years ago

Read 2 more answers

If x = a cosθ and y = b sinθ , find second derivative

Olin [163]

I'm guessing the second derivative is for <em>y</em> with respect to <em>x</em>, i.e.

$\dfrac{\mathrm d^2y}{\mathrm dx^2}$

Compute the first derivative. By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}$

We have

$y=b\sin\theta\implies\dfrac{\mathrm dy}{\mathrm d\theta}=b\cos\theta$

$x=a\cos\theta\implies\dfrac{\mathrm dx}{\mathrm d\theta}=-a\sin\theta$

and so

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{b\cos\theta}{-a\sin\theta}=-\dfrac ba\cot\theta$

Now compute the second derivative. Notice that $\frac{\mathrm dy}{\mathrm dx}$ is a function of $\theta$ ; so denote it by $f(\theta)$ . Then

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm dx}$

By the chain rule,

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm df}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}$

We have

$f=-\dfrac ba\cot\theta\implies\dfrac{\mathrm df}{\mathrm d\theta}=\dfrac ba\csc^2\theta$

and so the second derivative is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\frac ba\csc^2\theta}{-a\sin\theta}=-\dfrac b{a^2}\csc^3\theta$

4 0

2 years ago