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Lelechka [254]
2 years ago
15

Which step is the same when constructing an inscribed square and an inscribed regular hexagon?

Mathematics
2 answers:
Yanka [14]2 years ago
8 0

Answer:

  Construct a circle first

Step-by-step explanation:

If you're going to inscribe any figure in a circle, the first construction you need to do is <em>construct the circle</em>.

__

<em>Additional comment</em>

The attached shows our construction of an inscribed square and an inscribed regular hexagon. Here are the steps we used. You will notice the first step is <em>construct a circle</em>. (It could be, <em>construct line AB</em>, then construct circle A with radius AB.)

We have used line AB in the construction of the hexagon, but the hexagon could have been constructed without it. That is why "construct a circle first" is likely a better choice for a common first step.

<u>square</u>

  1. construct circle A and locate a point B on it
  2. construct line AB, and locate point C at the other intersection of AB and circle A
  3. set the compass to greater than half the diameter
  4. using B as a center, draw arc RS
  5. using C as a center, draw arc RS using the same compass setting. Label the intersection points R and S.
  6. draw line RS. Label the points of intersection with the circle as T and U.
  7. draw inscribed square CTBU

<u>regular hexagon</u>

  1. construct circle A and locate a point B on it
  2. construct line AB, and locate point C at the other intersection of AB and circle A
  3. without changing the compass, using B as a center, draw arc KL. Label intersection points K and L.
  4. using C as a center, draw arc JM. Label intersection points J and M.
  5. draw inscribed hexagon CJKBLM

__

Arguably, the first step to constructing a circle is <em>set the compass to the radius</em>. We chose to ignore this because one of the ways to construct an inscribed hexagon is to mark off successive arcs around a circle that have a radius equal to the radius of the circle. We did not use that method. (The use of diameter BC made drawing 5 arcs around the circle unnecessary. We drew 2 instead.)

Or, you could argue that <em>construct a line first</em> is needed before you set the compass to the radius. If this is the first step, then the next steps would be to <em>mark the center of the circle</em> on the line, and <em>mark another point at a distance of the radius</em> from that center point.

What you consider to be the first step depends on the level of detail you want to attend to.

Colt1911 [192]2 years ago
6 0

After the construction of a circle, we have to "Set the compass to the radius of the circle" so, option C is correct.

<h3>What is a regular hexagon?</h3>

A regular hexagon is defined as a closed shape consisting of six equal sides and six equal angles. The sum of the measure of angles of a regular hexagon is 120 degrees.

Steps to create an inscribed hexagon:

1: The structure needs to adjust the box thickness towards that radius.

2: Afterward moves around the outside of the circular path to just produce the 6 vertices of that similar hexagon.

"Set the compass to the radius of the circle" so, option C is correct.

Thus the above answer is correct.

Learn more about inscribed hexagons here:

brainly.com/question/21502832

#SPJ1

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We do prime factorization to get the age combination.

72 ÷ 2 = 36
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Possible combination with no repeating number.

1 x 8 x 9 = 72
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4 0
3 years ago
The theoretical probability of an event occurring is 2/5. Which best describes the experiment probability associated with this e
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The answer is out of every 5, the desired out come will be approximately 2 times. 
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3 years ago
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Root 3 cosec140° - sec140°=4<br>prove that<br><br>​
Lorico [155]

Answer:

Step-by-step explanation:

We are to show that \sqrt{3} cosec140^{0} - sec140^{0} = 4\\

<u>Proof:</u>

From trigonometry identity;

cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}

\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\

From trigonometry, 2sinAcosA = Sin2A

= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\=  \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\=  \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2  \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}

Also note that sin(B-C) = sinBcosC - cosBsinC

sin420cos140 - cos420sin140 = sin(420-140)

The resulting equation becomes;

\frac{4(sin(420-140)) }{sin280}

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3 0
3 years ago
Someone please help me
yuradex [85]

Answer:

112in²

Step-by-step explanation:

Formulas: V = \frac{lwh}{3}, V = lwh

Sub: v = \frac{4 x 4 x 6}{3}

Solve: 32

Sub: v = 4 x 4 x 5

Solve: 80

V = 80 + 32

V = 112

<u>The total volume of the figure is 112in²</u>

3 0
3 years ago
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ziro4ka [17]

Answer:

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Step-by-step explanation:

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0.358659 (bolded)

so, since the 9 rounds up, the estimated number would be 0.35866

the numbers before would be 0.35865 and after, 0.35867

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