Narrow
it describes a path lined with flowers
A quadratic function is a function of the form
![f(x)=ax^2+bx+c](https://tex.z-dn.net/?f=f%28x%29%3Dax%5E2%2Bbx%2Bc)
. The
vertex,
![(h,k)](https://tex.z-dn.net/?f=%28h%2Ck%29)
of a quadratic function is determined by the formula:
![h= \frac{-b}{2a}](https://tex.z-dn.net/?f=h%3D%20%5Cfrac%7B-b%7D%7B2a%7D%20)
and
![k=f(h)](https://tex.z-dn.net/?f=k%3Df%28h%29)
; where
![h](https://tex.z-dn.net/?f=h)
is the
x-coordinate of the vertex and
![k](https://tex.z-dn.net/?f=k)
is the
y-coordinate of the vertex. The value of
![a](https://tex.z-dn.net/?f=a)
determines if the <span>
parabola opens upward or downward; if</span>
![a](https://tex.z-dn.net/?f=a)
is positive, the parabola<span> opens upward and the vertex is the
minimum value, but if </span>
![a](https://tex.z-dn.net/?f=a)
is negative <span>the graph opens downward and the vertex is the
maximum value. Since the quadratic function only has one vertex, it </span><span>could not contain both a minimum vertex and a maximum vertex at the same time.</span>
All you need to do for this is to plug in the given values for the radius and the height to solve for volume. You won't actually get a number answer, because there are variables, but this is what the problem gives us, so that's what we'll use.
Volume= pi(r^2)(h)
V=pi((x+8)^2)(2x+3)
V=pi(x^2+16x+64)(2x+3)
V=pi(2x^3+3x^2+32x^2+48x+128x+132)
V=pi(2x^3+35x^2+176x+132)
The answer to your question is C 26%