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dmitriy555 [2]
3 years ago
9

A math test is worth 100 points and has 38 problems. each problem is worth either 5 points or 2 points. how many problems of eac

h point value are on the test? there are 8 five-point problems.
Mathematics
2 answers:
Tanzania [10]3 years ago
8 0
If there are eight five point problems, that is forty points already.  There are sixty points left and all of them must be two point problems, so there are 30 two point problems and 8 five point problems.  Please mark Brainliest!!!
blondinia [14]3 years ago
4 0
Hey there,
There are 2 ways
1st way:
Since there are 8 5 point problems, 38 - 8 = 30, will give you the 2 point problems.

2nd way: 
8 x 5 = 40
100 - 40 = 60
60 / 2 = 30
Thus there are 30, 2 point problems.

Hope this helps :))

~Top
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Step-by-step explanation:

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PLEASE HELP!!!!
Mandarinka [93]

Answer:

C) If you live in a mansion, then you do not have a small lawn to mow.

Step-by-step explanation:

<u> Statement is </u>

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<u>Equivalent statements to the given one: </u>

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8 0
3 years ago
Solve for X<br><br> Log x - log 3 = log(x-2)<br><br> Please please help
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Step-by-step explanation:

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Bingel [31]
Combine the 2nd and 3rd equations.  3x will disappear:

 2y + 5z = 7  This is true for any y and z, and is independent of x.
 
                                                            7-5z
Solving for y, 2y = 7 - 5z, so that y = ---------
                                                               2

We have to eliminate x again by using the 1st and 2nd equations:

 -2x - 6y - 2z = -2.  We want the coeff. of x in the first eqn to be -3.  

Therefore, mult. all terms of  -2x - 6y - 2z = -2  by 3/2:

(3/2)(-2x - 6y - 2z = -2) = -3x -9y  -3z =-3

Now add this version of the 1st row to the 2nd row:

  -3x -9y  -3z =-3
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----------------------
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                                          7 - 5z
We found earlier that y = ----------, and can elim. y by subst. this fraction into 
                                              2

 -7y + 2z = 4.  Then     -7y + 2z = 4 becomes   -7( (7-5z)/2 ) + 2Z = 4.

Elim. the fraction by mult. all terms by 2:

-7(7-5z) + 4z = 8    which becomes    -49 + 35z + 4z = 8

so that 39z = 57, and so z = 57/39.

Subst. this back into -7y + 2z = 4 to calculate y.  Make a final subst. to calculate x.

Given the choice, I would solve this system using matrices.

Turns out that the solution, using matrices, does not exist.


                                             
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Ivenika [448]
The correct answer to your question is
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