What is 200 increased by 18%

2 answers:

8 0

That would 236 because you must take the percentage which is 18% and turn it into a decimal like this .18 then you must multiply that by 200 whch will give you 36. The last thing you must do is add the 200 in side of the equation which will give you 236.

kati45 [8]4 years ago

7 0

Ok, so to increase 200 by 18%, you want to know how much is 1% of 200. So, in order to figure this out, you want to divide 200 by 100, to get 2. So, you know that 2 is 1% of 200. Now, to increase 200 b 18%, you will want to multiply 18 by 2, to get 26. So, the final answer is 236.

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sweet-ann [11.9K]

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6 0

3 years ago

Read 2 more answers

Peter planted 5/12 of his garden with asparagus and 3/12 with beans.

UkoKoshka [18]

Answer: He has planted 2/3 and there is 1/3 left to plant.

Explanation: You need to add your fractions together, because each of those is a section of the garden and you need the total of how much of the garden he has planted.

This isn’t too difficult because the denominators are the same.

5/12 + 3/12 = 8/12

It is 8/12 because since the denominators are the same, you just need to add the numerators. Imagine you have a pie that’s cut into 12 pieces, and you and your friends take 5, and then your family takes 3. How many or gone now? 8 pieces. From how many pieces? 12 pieces. So 8/12 pieces are gone.

So Peter has planted 8/12 of his garden. This however, can be simplified, because both of those numbers divide by 4.

8/4 = 2
12/4 = 3

So 8 is now 2, and 12 is now 3.

This is now 2/3.

If there is 2/3 gone, you need to figure out how much is left to get you to 1.

In this instance, 1 can be rewritten as 3/3, because 3 divided by 3 is 1.

In order to get from 2/3 to 1, you need to add 1/3, one more third to the two thirds you already have.

This means Peter has 1/3 left to plant.

Hope this helps :)

7 0

3 years ago

What are the key aspects of the graph of f(x) = x2 – b2, where b is a real number?

netineya [11]

Given equation is $f\left(x\right)=x^2-b^2$ .

Now we need to find about what are the key aspects of the graph of $f\left(x\right)=x^2-b^2$ , where b is a real number.

We know that square of any number is always positive.

then $b^2$ must be a positive number.

So that means for any real number b, as the value of b increases then graph of f(x) shifts downward by $b^2$ units as compared to the graph of parent function $f\left(x\right)=x^2$