Question

on 1st jan 2016, sanika decides to save 10( rupees),11(rupees)on second day, 12(rupees) on third day. if she decides to save like this, then on 31st Dec 2016 what would be her total saving??​

Answer 1

her total savings in 1 year =rs 70455

Answer:

first term a=rs 10

second term b =11

common difference d=11-10=1

n=366days because 2016 is leap year

now

Sn=n/2[2a+(n-1)d]

S365 =366/2[2×10+(366-1)1]

=366/2[20+365]

=rs70455