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jeka57 [31]
3 years ago
14

Use the divided by 10 pattern to fill in the blanks 400

Mathematics
1 answer:
ra1l [238]3 years ago
3 0
The answer must have to be 40
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A city is 7,642 feet above sea level. Is this elevation closer to the highest point or the lowest point?
tekilochka [14]

Answer:

It must be closer to the lowest point.

Step-by-step explanation:

There is a simple and a general explanation to it. As it gets higher up from the sea level, the elevation gets closer to the lowest point simply because the distance from the highest point keeps decreasing as you get closer. The elevation is the distance left between the highest point and the current point.

3 0
3 years ago
Help math help 50 points I need alll the questions answered. Help ASAP no links or imma report you.
Ganezh [65]

Answer:

Step-by-step explanation:

x+y = 6

y = (6-x)

7x +12y = 52

7x+12(6-x) = 52

7x +72 -12x = 52

-5x = -20

x= 4     4 days at $7  = $28

           2 days at $12 = $24

 28+24 = 52

4 0
3 years ago
HELLLLLLLLPPPPPPPPPPPP,
Marat540 [252]

Answer:

-1/12

Step-by-step explanation:

12x-3 = -4

12x= -1

x= -1/12

6 0
3 years ago
Find the slope between (-4,1) and (-2,-2)
alukav5142 [94]

Answer:

-1.5

Step-by-step explanation:

y=-1.5x-5

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3 years ago
Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46
JulsSmile [24]

Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

a. What is the point estimate of the mean salary for all college graduates in this town?

Mean of the bounds, so:

(38737+50463)/2 = 44600.

The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

M = \frac{50463-38737}{2} = 5863

Relating the margin of error with the sample size:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.64.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

For this problem, we have that \sigma = 14300, M = 5863. So

M = z\frac{\sigma}{\sqrt{n}}

5863 = 1.645\frac{14300}{\sqrt{n}}

5863\sqrt{n} = 1.645*14300

\sqrt{n} = \frac{1.645*14300}{5863}

(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2

n = 16

The sample size was of 16.

7 0
3 years ago
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