Use the divided by 10 pattern to fill in the blanks 400

valentinak56 [21]

Really night what's the problem

7 0

3 years ago

When Jennifer purchases her house, she pays a 3% realtor commission for the $1800,000 loan amount. How much commission did Jenni

ankoles [38]

Answer:

$54,000

Step-by-step explanation:

1,800,000 - 3% =

1,746,000

1,800,000 - 1,746,000 =

54,000

Jennifer paid $54,000 commission fee

8 0

2 years ago

Marcus needs 108 inches of wood to make a frame. How many feet of wood does Marcus need for the frame?

ludmilkaskok [199]

9 inches, divide 108 by 12, because 12 inches makes a foot

3 0

3 years ago

A coin is thrown independently 10 times to test the hypothesis that the probability of heads is 0.5 versus the alternative that

mafiozo [28]

Answer:

(a) The significance level of the test is 0.002.

(b) The power of the test is 0.3487.

Step-by-step explanation:

We are given that a coin is thrown independently 10 times to test the hypothesis that the probability of heads is 0.5 versus the alternative that the probability is not 0.5.

The test rejects the null hypothesis if either 0 or 10 heads are observed.

Let p = <u><em>probability of obtaining head.</em></u>

So, Null Hypothesis, $H_0$ : p = 0.5

Alternate Hypothesis, $H_A$ : p $\neq$ 0.5

(a) The significance level of the test which is represented by $\alpha$ is the probability of Type I error.

Type I error states the probability of rejecting the null hypothesis given the fact that the null hypothesis is true.

Here, the probability of rejecting the null hypothesis means we obtain the probability of observing either 0 or 10 heads, that is;

P(Type I error) = $\alpha$

P(X = 0/ $H_0$ is true) + P(X = 10/ $H_0$ is true) = $\alpha$

Also, the event of obtaining heads when a coin is thrown 10 times can be considered as a binomial experiment.

So, X ~ Binom(n = 10, p = 0.5)

P(X = 0/ $H_0$ is true) + P(X = 10/ $H_0$ is true) = $\alpha$

$\binom{10}{0}\times 0.5^{0} \times (1-0.5)^{10-0} +\binom{10}{10}\times 0.5^{10} \times (1-0.5)^{10-10}$ = $\alpha$

$(1\times 1\times 0.5^{10}) +(1 \times 0.5^{10} \times 0.5^{0})$ = $\alpha$

$\alpha$ = 0.0019

So, the significance level of the test is 0.002.

(b) It is stated that the probability of heads is 0.1, and we have to find the power of the test.

Here the Type II error is used which states the probability of accepting the null hypothesis given the fact that the null hypothesis is false.

Also, the power of the test is represented by (1 - $\beta$ ).

So, here, X ~ Binom(n = 10, p = 0.1)

$1-\beta$ = P(X = 0/ $H_0$ is true) + P(X = 10/ $H_0$ is true)

$1-\beta$ = $\binom{10}{0}\times 0.1^{0} \times (1-0.1)^{10-0} +\binom{10}{10}\times 0.1^{10} \times (1-0.1)^{10-10}$

$1-\beta$ = $(1\times 1\times 0.9^{10}) +(1 \times 0.1^{10} \times 0.9^{0})$

$1-\beta$ = 0.3487

Hence, the power of the test is 0.3487.

3 0

3 years ago

The average of eight numbers is 56. When one of the numbers was left out, the mean decreased to 54. What number was left out?

Alexandra [31]

The number that was left out is 70.

<h3>What is the number that was left out?</h3>

Average is the sum of a set of numbers divided by the total numbers in the data set.

Average = sum of numbers / total numbers

Sum of numbers when there are 8 numbers = 56 x 8 = 448
Sum of numbers when there are 7 numbers = 54 x 7 = 378
Difference = 448 - 378 = 70

To learn more about average, please check: brainly.com/question/25842202

#SPJ1

4 0

2 years ago