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Brut [27]
3 years ago
8

Solve for x in the triangle above

Mathematics
1 answer:
faust18 [17]3 years ago
8 0

Answer:

x = 30

Step-by-step explanation:

The interior angles of a triangle must always add up to 180.

2x + 2x + 3x - 30 = 180

Add 30 to both sides to seperate variables.

2x + 2x + 3x = 210

Combine like terms.

7x = 210

Divide by 7 to isolate x.

x = 30

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8_murik_8 [283]

Answer:

3(x^y(5x^2y-x³)+25x⁴))

Step-by-step explanation:

15x^2y²-3x^3y+75x⁴

From 15x^2y²-3x^3y only, 3x^y is the common factor

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Taking the common factor of the latter expression, 3 shows to be the common factor of all the expression.

=> 3(x^y(5x^2y-x³)+25x⁴)

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3 years ago
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3 years ago
Are any of these functions?
Kaylis [27]

Answer:

No, they are not.

Step-by-step explanation:

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3 0
4 years ago
Help me with these please​
olchik [2.2K]

Step-by-step explanation:

(1) y = x e^(x²)

Take derivative with respect to x:

dy/dx = x (e^(x²) 2x) + e^(x²)

dy/dx = 2x² e^(x²) + e^(x²)

dy/dx = (2x² + 1) e^(x²)

Take derivative with respect to x again:

d²y/dx² = (2x² + 1) (e^(x²) 2x) + (4x) e^(x²)

d²y/dx² = (4x³ + 2x) e^(x²) + 4x e^(x²)

d²y/dx² = (4x³ + 6x) e^(x²)

Substitute:

d²y/dx² − 2x dy/dx − 4y

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= 4x³ + 6x − 4x³ − 2x − 4x

= 0

(2) y = sin⁻¹(√x)

sin y = √x

sin²y = x

Take derivative with respect to x:

2 sin y cos y dy/dx = 1

sin(2y) dy/dx = 1

dy/dx = csc(2y)

Take derivative with respect to x again:

d²y/dx² = -csc(2y) cot(2y) 2 dy/dx

d²y/dx² = -2 csc²(2y) cot(2y)

Substitute:

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Use power reduction formula:

= (1 − cos(2y)) (1 − ½ (1 − cos(2y))) (-2 csc²(2y) cot(2y)) + (1 − (1 − cos(2y))) csc(2y)

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= -sin²(2y) csc²(2y) cot(2y) + cot(2y)

= -cot(2y) + cot(2y)

= 0

8 0
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Rzqust [24]

Answer:

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Step-by-step explanation:

6*4=24

24/3=8

8*2=16

the answer is 16

8 0
3 years ago
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