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3 years ago

Kelly has to read a 15 page poem she has read 10 pages so far,what fraction of the poem did she read?

Mathematics

2 answers:

andrew-mc [135]3 years ago

7 0

Kelly has read 2/3 of her book so far

Free_Kalibri [48]3 years ago

5 0

Answer:

Kelly has read 2/3 of the poem.

Step-by-step explanation:

If you divide the 10 pages she has read by the total 15 pages, you get 0.66. Another way to get this is to put 10 over 15. Divide both the numerator and denominator by 5 to get 2/3.

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8.(01.02)

Nadusha1986 [10]

Answer:

Step-by-step explanation:

so the g(x) = x-1 gets plugged into every x in the f(x) function

= $(x-1)^{2}$ - 3(x-1) + 3

= $x^{2}$ -2x+1 -3x +3 + 3

= $x^{2}$ -5x +7

now plug in x = 5

= $5^{2}$ -5(5) +7

= 7

6 0

3 years ago

Shelly sells cars, and she has to sell 50 cars per month t get a bonus. If Shelly sold 28% of the number of cars needed to get a

andrew-mc [135]

Answer: 14

Step-by-step explanation:

28% of 50

3 0

3 years ago

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Which of these equations has a solution of x = 2? Select three that apply. A 6(2x – 1) = 4 + 7x B 10 – 3x = –2(x + 4) C –3(7 – 2

Nesterboy [21]

Answer:

x = 2 for a, c, and f

Step-by-step explanation:

6(2x - 1) = 4 + 7x

12x - 6 = 4 + 7x

5x = 10

x = 2

10 - 3x = -2(x + 4)

10 - 3x = -2x - 8

18 = x

-3(7 - 2x) = -1 - 4x

-21 + 6x = -1 - 4x

10x = 20

x = 2

7x + 12 = 2(4x - 5)

7x + 12 = 8x - 10

22 = x

-5(x + 1) = -4 - 7x

-5x - 5 = -4 - 7x

2x = 1

x = 1/2

8x + 11 = 9(5 - x)

8x + 11 = 45 - 9x

17x = 45 - 11

17x = 34

x = 2

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3 years ago

Find the slope of the line hurry!

Furkat [3]

Answer:

the slope is 3 :)

Step-by-step explanation:

6 0

3 years ago

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Help with number 6 please. thank you.

Gwar [14]

Answer:

See Below.

Step-by-step explanation:

We are given that:

$\displaystyle \frac{dT}{dt} = -k(T - T_0)$

And we want to show that:

$\displaystyle T = T_0+Ae^{-kt}$

From the original equation, divide both sides by (T - T₀) and multiply both sides by dt. Hence:

$\displaystyle \frac{dT}{T-T_0}= -k\, dt$

Take the integral of both sides:

$\displaystyle \int \frac{dT}{T- T_0} = \int -k \, dt$

Integrate. For the left integral, we can use u-substitution. Note that T₀ is simply a constant. Hence:

$\displaystyle \ln\left|T - T_0\right| = -kt+C$

Raise both sides to e:

$\displaystyle e^{\ln\left|T-T_0\right|} = e^{-kt+C}$

Simplify:

$\displaystyle \begin{aligned} \left| T- T_0\right| &= e^{-kt} \cdot e^C \\ \\ &= e^C\left(e^{-kt}\right) \\ \\ &=Ae^{-kt} & \text{Let $e^C = A$}\end{aligned}$

Since the temperature T will always be greater than or equal to the surrounding medium T₀, we can remove the absolute value. Hence:

$\left(T - T_0\right) = Ae^{-kt}$

Therefore:

$\displaystyle T = T_0+Ae^{-kt}$

5 0

3 years ago

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