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Darya [45]
3 years ago
10

Find the area of Triangle A in square centimeters.

Mathematics
1 answer:
forsale [732]3 years ago
6 0

Answer is in the photo. I can't attach it here, but I uploaded it to a file hosting. link below! Good Luck!

tinyurl.com/wpazsebu

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of the 200 guests thay attended a party,132 brought a present for the host .what percent of the guests broight a present ?
nordsb [41]
132/ 200 = .66
66 percent of guests brought a present.
5 0
3 years ago
A combination lock uses three numbers between 1 and 46 with​ repetition, and they must be selected in the correct sequence. Is t
vladimir2022 [97]

The correct answer is D. ​No because the permutations rule would be used to determine the total number of combinations.

Explanation:

The difference between a combination and a permutation is that in permutations the order is considered. This applies to the numbers in a lock because these need to be in order. Therefore, to analyze the permutations in a lock, the rule for permutations should be used. This includes the general formula P (n,r) =\frac{n!}{(n-r) !}; in this, n is the number of objects and r refers to the objects used in a permutation. Thus, the term "combination" is inappropriate because this is a permutation, and the permutation rule should be used.

8 0
4 years ago
I know I'm like helping many, but I still need help too people's so please help
quester [9]
Sylvia is correct because a right triangle needs to have 1 right angle and 2 acute angles, it cannot have more than 1 right angle.
6 0
3 years ago
Factor x3y6 + 27z42. (xy3 + 3z39)(x2y9 – 3xy3z39 + 9z1,521) (xy3 + 3z39)(x2y6 – 3xy3z39 + 9z78) (x3y6 + 27z42)(x6y12 – 27x3y6z42
Licemer1 [7]

Answer:

x^3y^6 + 27z^{42} = (xy^2 + 3z^{14})(x^2y^4 - 3xy^2z^{14} + 9z^{28})

Step-by-step explanation:

Given

x^3y^6 + 27z^{42

Required

Factor

Express both terms as a cube

x^3y^6 + 27z^{42} = (xy^2)^3 + (3z^{14})^3

Let

a =(xy^2)

b = (3z^{14})

So:

x^3y^6 + 27z^{42} = a^3 + b^3

Using sum of cubes:

a^3 + b^3 = (a + b)(a^2 - ab + b^2)

So:

x^3y^6 + 27z^{42} = (a + b)(a^2 - ab + b^2)

Substitute in, values of a and b

x^3y^6 + 27z^{42} = (xy^2 + 3z^{14})((xy^2)^2 - (xy^2)*(3z^{14}) + (3z^{14})^2)

x^3y^6 + 27z^{42} = (xy^2 + 3z^{14})(x^2y^4 - 3xy^2z^{14} + 9z^{28})

5 0
3 years ago
Read 2 more answers
0+2=-2/3(x-6) <br> What is X?
ioda

Answer:

x=3

Step-by-step explanation:

Hope it helps youuuuuu

7 0
3 years ago
Read 2 more answers
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