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Nana76 [90]
3 years ago
7

How many ways can the teacher choose a group of 5 students to present on the first day if Marjorie must present on the first day

?
Mathematics
1 answer:
Nata [24]3 years ago
3 0
15 ways a teacher can chose the group
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Determine the value of the variable. 5 + 17 = J - 14
Nataly_w [17]
You would add 5 and 17 and that would equal 22
Now it would be 22=J-14
Then add 14 on both sides so it cancels out 22 plus 14 is 36
So J would equal 36
3 0
3 years ago
Read 2 more answers
Find the greatest common factor of 15x^2 y^3 and -20x^3 yz
Elza [17]
5x^2y is the answer which leaves you with 3y^2 and -4xz
7 0
4 years ago
A large school district in Connecticut wants to estimate the average SAT score of this year's graduating class using a 95% confi
forsale [732]

Answer:

[ 502.5, 517.5]

Step-by-step explanation:

Given:

Mean of the sample, µ = 510

Total sample size, n = 100

Standard deviation = 75

Confidence level = 95%

Now,

The interval for µ is given as:

⇒ µ ± z\frac{\sigma}{\sqrt n}

for 95% confidence level z value = 1.96

Thus,

The interval for µ

⇒ 510 ± 1.96\times\frac{75}{\sqrt{100}}

or

⇒ 510 ± 7.5

or

⇒ [ 510 - 7.5, 510 + 7.5 ]

or

⇒ [ 502.5, 517.5]

7 0
3 years ago
4x+7=23. explain the steps you would use to solve the equation for x.​
yaroslaw [1]

Answer:

x=4

Step-by-step explanation:

1. isolate the variable by subtracting 7 on both sides: 4x=23-7

2. simplify: 4x=16

3. divide both sides by 4: x=16/4

4. simplify: x=4

5 0
3 years ago
Read 2 more answers
Which of the following is the complete list of roots for the polynomial function f(x)=(x^2+6x+8)(x^2+6x+13)
MrMuchimi

Answer:

<h2>x = -4 or x = -2</h2>

Step-by-step explanation:

f(x)=(x^2+6x+8)(x^2+6x+13)\\\\f(x)=0\iff(x^2+6x+8)(x^2+6x+13)=0\iff\\x^2+6x+8=0\vee x^2+6x+13=0\\\\x^2+6x+8=0\\x^2+4x+2x+8=0\\x(x+4)+2(x+4)=0\\(x+4)(x+2)=0\iff x+4=0\ \vee\ x+2=0\\x+4=0\qquad\text{subtract 4 from both sides}\\\boxed{x=-4}\\x+2=0\qquad\text{subtract 2 from both sides}\\\boxed{x=-2}\\\\x^2+6x+13=0\qquad\text{subtract 13 from both sides}\\x^2+6x=-13\\x^2+2(x)(3)=-13\qquad\text{add}\ 3^2=9\ \text{to both sides}\\x^2+2(x)(3)+3^2=-13+9\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\(x+3)^2=-4

8 0
3 years ago
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