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madreJ [45]
3 years ago
15

0.25 , 0.5 , 0.375 , 2.5 , 0.125 in asending order ..​

Mathematics
1 answer:
borishaifa [10]3 years ago
6 0
0.125 is the CLOSEST to 0 while 2.5 is the FARTHEST. Using this as a guide, the order is: 0.125, 0.25, 0.375, 0.5, 2.5. Hope this helped :)
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Manuel has a boat that can move at a speed of 15 km/h in still water. He rides 140 km downstream in a river in the same time it
Anika [276]

Answer: the speed of the river is 9km/h

Step-by-step explanation:

Let x represent the speed of the river current.

He rides 140 km downstream in a river in the same time it takes to ride 35km upstream. This means that his speed was higher when riding downstream and it was lower when riding upstream.

Assuming he rode in the direction of the river current when coming downstream and rode against the current when going upstream.

time = distance/speed

Manuel has a boat that can move at a speed of 15 km/h

His downstream speed would be

15 + x

time spent coming downstream would be

140/(15 + x)

His downstream speed would be

15 - x

time spent going downstream would be

35/(15 - x)

Since the time is the same, then

140/(15 + x) = 35/(15 - x)

Crossmultiplying

140(15 - x) = 35(15 + x)

2100 - 140x = 525 + 35x

140x + 35x = 2100 - 525

175x = 1575

x = 1575/175

x = 9

7 0
4 years ago
A parallelogram has a base of 10 centimeters and a height of 4 centimeters. What is the area of the parallelogram?
Illusion [34]

Step-by-step explanation:

Area of a parallelogram=base×height

=10×4

=40cm^2

5 0
3 years ago
85,109,178 in world form
igor_vitrenko [27]
Eighty five million, one hundred nine thousand, one hundred seventy-eight. 
5 0
3 years ago
Helpppppp me pleaseeeee<br> Divide the following integers. -12 � 4= -3 -8 -48 3
Orlov [11]

Answer:

Step-by-step explanation:

Simplify  -12\ 4−12÷4  to  -3−3.

-3=-3-8-48,3

−3=−3−8−48,3

2 Simplify  -3-8−3−8  to  -11−11.

-3=-11-48,3

−3=−11−48,3

3 Simplify  -11-48−11−48  to  -59−59.

-3=-59,3

−3=−59,3

4 Since -3=-59,3−3=−59,3 is false, there is no solution.

4 0
3 years ago
What are the coordinates of the endpoints of the midsegment for DEF that is parallel to DE
Nutka1998 [239]

Answer:

\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right),  \left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).

Step-by-step explanation:

Let points D, E and F have coordinates (x_D,y_D),\ (x_E,y_E) and (x_F,y_F).

1. Midpoint M of segment DF has coordinates

\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right).

2. Midpoint N of segment EF has coordinates

\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).

3. By the triangle midline theorem, midline MN is parallel to the side DE of the triangle DEF, then points M and N are endpoints of the midsegment for DEF that is parallel to DE.

6 0
3 years ago
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