Rewrite without parentheses and simplify.<br> (3u-8v)^2 BOX METHOD

PLEASE HELP PEOPLE MAKE IT LOOK LIKE THEY ARE ANSWERING IT THEN THEY QUIT PLEASE HELP

Paha777 [63]

The solutions to f(x) = 64 is x = 7 and x = –7.

Solution:

Given data:

$$f(x)=x^{2}+15$ and $f(x)=64$

To find the solutions when f(x) = 64.

Both are equations of f(x), so equate the given equations, we get

$x^2+15=64$

Subtract 15 from both sides of the equation.

$x^2+15-15=64-15$

$x^2=49$

49 can be written as 7².

$x^2=7^2$

Taking square root on both sides of the equation, we get

x = ±7

The solutions to f(x) = 64 is x = 7 and x = –7.

3 0

3 years ago

One x-intercept for a parabola is at the point (4,0). Find the other x-intercept for the parabola defined by this equation y=x^2

yanalaym [24]

Probably the easiest way to do this is to use synthetic division. We already know one of the zeros of the quadratic so we can use that number to find the other zero. If the point is (4, 0), then when y = 0, x = 4. Thus, 4 is a zero. Put 4 outside the "box" and put the coefficients from the quadratic inside, like this: 4 (1 -1 -12). Draw a line and bring down the first one under it. Multiply that 1 by the 4 to get 4. Put that 4 up under the -1 and add to get 3. Multiply 3 by 4 to get 12. Put that 12 up under the -12 and add to get 0. The numbers left under the line are the coefficients for the next polynomial, called the depressed polynomial, and this polyomial is one degree less than the one we started with. Those coefficients are 1 and 3. Therefore, the polynomial is x + 3 = 0. That means that the other zero, or x-intercept, is x = -3.

6 0

4 years ago

A bank's loan officer rates applicants for credit. The ratings are normally distributed with a mean of 200 and a standard devia

Butoxors [25]

Answer:

Probability that their mean is above 215 is 0.0287.

Step-by-step explanation:

We are given that a bank's loan officer rates applicants for credit. The ratings are normally distributed with a mean of 200 and a standard deviation of 50.

For this, 40 different applicants are randomly selected.

<em>Let X = ratings for credit</em>

So, X ~ N( $\mu=200,\sigma^{2}=50^{2}$ )